Given :
Compound A reacts with Compound B to form only one product, Compound C.
The usual percent yield of C in this reaction is 40%.
10.0 g of A are reacted with excess Compound B, and 6.4 g of Compound C
To Find :
The theoretical yield of C.
Solution :
We know, % yield is given by :
Putting given values , we get :
Therefore, theoretical yield of C is 16 g.
Hence, this is the required solution.
For every 1 molecule of Magnesium hydroxide or Mg(OH)2 there will be 2 molecules of HCl neutralized.
If molar mass of magnesium hydroxide is 58.3197g/mol, the amount of mol in 5.50 g magnesium hydroxide should be: 5.50g/ (<span>58.3197g/mol)= 0.0943mol.
Then, the amount of HCl molecule neutralized would be: 2* </span>0.0943mol= 0.18861 mol
If molar mass of HCl is 36.46094 g/mol, the mass of the molecule would be: 0.18861 mol* 36.46094g/mol = 6.88grams
Answer:
<h2>
<em>no</em></h2>
Explanation:
<h2><u><em>
the particles in gas move so freely that it cannot have a definite density</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
moo</em></u></h2>
pretty sure its B thank me later
Medium about 3 second? Not sure lol just need more points honestly lol
