Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
<h3>
Inscribing a square</h3>
The steps involved in inscribing a square in a circle include;
- A diameter of the circle is drawn.
- A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
- The resulting four points on the circle are the vertices of the inscribed square.
Alicia deductions were;
Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle
Benjamin's deductions;
The diameters must be perpendicular to each other. Then connect the points, in order, around the circle
Caleb's deduction;
No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.
It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.
Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
Learn more about an inscribed square here:
brainly.com/question/2458205
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Answer:
49 percent
Step-by-step explanation:
So convert the fraction into a percentage
245/500= 49%
A line is a set of points that has no beginning and no end.
The answer would be 68x-72
Answer is a= 51/7 or 7 2/7
Step by step
-2/3 (a + 3) = 5/3a - 19
Distribute to resolve parentheses
-2/3a -2 = 5/3a - 19
Now to move variables to one side
Add 2/3a to both sides
-2/3a + 2/3a -2 = 5/3a + 2/3a -19
Combine like terms
-2 = 7/3a -19
Add 19 to both sides to isolate variable
-2 +19 = 7/3a -19 + 19
17 = 7/3a
Divide both sides by 7/3 to solve for a
(Remember when you divide a fraction, flip it and multiply.)
17 * 3/7 = a
51/7 = a
Picture attached shows steps in order, I think that is what you also needed?