Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.
<h3>
Conservation of Linear Momentum</h3>
It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.
Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.
The given parameters are;
The formula to find the speed will be
M1U1 - M2U2 = (M1 + M2)V
7500 × 5 - 1500 × 10 = (7500 + 1500)V
37500 - 15000 = 9000V
22500 = 9000V
V = 22500/9000
V = 2.5 m/s
Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.
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Answer:
At the midpoint of the line joining the two equal charges
Explanation:
The midpoint of the line joining the two equal charges has equal distance from each charge. Since the charges are at x = a and x = -a, at the midpoint of the line joining the two equal charges, the magnitude of the electric field experienced as a result of each charge is the same. But these two fields are in opposite direction, hence the net resulting electric field would be equal to zero.
There are always new questions to answer and new problems to solve in this area. The correct option is D.
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It is a necessary skill for supervisors and other senior positions. Individuals who have excellent problem-solving skills are a precious and considered reliable attribute in any team.
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Thus, the correct option is D.
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