Answer:
a.)
I.) Open system
II.) Closed system
b.)
The total momentum of the object and earth system stay the same as the object fall toward the earth
The kinetic energy of the object increases as the object falls toward the earth.
Explanation:
a.)
I.) The system containing only the object is an open system because of the influence of external forces and presence of matters. External forces in this scenario means gravitational force acting on the object. And air is the matter that has influence on the object.
II.) The system containing only the object and earth is a closed system. Because in a closed system, there are no external dissipative forces acting on it. Universe is a closed system. And the mechanical energy of a close system is conserved. The mechanical energy will remain constant. In other words, it will not change (become more or less). This is called the Law of Conservation of Mechanical Energy.
b.) The total momentum of the object and earth system stay the same as the object fall toward the earth. Because momentum will always be conserved.
The kinetic energy of the object increases as the object falls toward the earth. When the object was initially at rest, kinetic energy equals zero
To solve this problem it is necessary to take into account the kinematic equations of motion and the change that exists in the volume flow.
By definition the change in speed is given by
Where,
x= distance
final velocity
initial velocity
a = acceleration
On the other hand we know that the flow of a fluid is given by
Where,
A = Area
v = Velocity
PART A )
Applying this equation to the previously given values we have to
Therefore the velocity of the water leaving the hole is 17.48m/s
PART B )
In the case of the hole we take the area of a circle, therefore replacing in the flow equation we have to,
The diameter is 2 times the radius, then is 
m or 1.91mm
<em>Note: The rate flow was converted from minutes to seconds.</em>
The magnitude of the air drag when the object is traveling at terminal velocity is C. 850 Newtons
Explanation:
There are only two forces acting on the object here:
- The force of gravity, of magnitude 
, acting downward
- The air drag, 
, acting upward
Therefore, the equation of motion for the object is
where m is the mass of the object and a its acceleration.
The object in this problem is traveling at terminal velocity: this means that the acceleration is zero, so
a = 0
Therefore the equation becomes
which means that the magnitude of the air resistance is equal to the magnitude of the force of gravity:
Learn more about acceleration and Newton laws of motion here:
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A lighted candle produces heat however not as much heat as a heater or the sun would.
<span>k = 1.7 x 10^5 kg/s^2
Player mass = 69 kg
Hooke's law states
F = kX
where
F = Force
k = spring constant
X = deflection
So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration.
F = kX
F/X = k
115 kg* 9.8 m/s^2 / 0.65 cm
= 115 kg* 9.8 m/s^2 / 0.0065 m
= 1127 kg*m/s^2 / 0.0065 m
= 173384.6154 kg/s^2
Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2
Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So
X/0.39 cm = 115 kg/0.65 cm
X = 44.85 kg/0.65
X = 69 kg
The player masses 69 kg.</span>
