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2 years ago

Name 3 renewable energy resources

Physics

2 answers:

Ad libitum [116K]2 years ago

7 0

Solar energy, wind energy, hydro energy

babymother [125]2 years ago

3 0

Tidal power, hydroelectricity, biomass

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What are the five practices in scientific inquiry

nata0808 [166]

1. Learners are engaged by scientifically oriented questions.
2. Learners give priority to evidence, allowing them to develop and
evaluate explanations that address scientifically-oriented questions.
3. earners formulate explanations form evidence to address scientifically
oriented question
4. Learners evaluate their explanations in light of alternative explanations,
particularly those reflecting scientific understanding.
5. Learners communicate and justify their proposed explanations.

5 0

3 years ago

a body of a mass 1kg suspended from a spring is found to stretch the spring by 10cm. (A) what is the spring constant? what is pe

Nikitich [7]

Answer:

(A) The spring constant is 98 N/m.

(B) The period of oscillation is 0.635 s.

Explanation:

Given:

Mass of the body is, $m=1\ kg$

Extension length of the spring is, $x=10\ cm=0.1\ m$

Now, let 'k' be the spring constant.

The force acting on the body is due to gravity only and is equal to its weight.

So, weight of the body is given as:

$F_g=mg\\F_g=1\times 9.8\\F_g=9.8\ N$

Now, we know that for a spring-mass system, the net force acting on the body is equal to the product of the spring constant and extension length. Therefore,

$F_g=kx\\9.8=k(0.1)\\k=\frac{9.8}{0.1}=98\ N/m$

Hence, the spring constant is 98 N/m.

(B)

Period of oscillation of a body of spring-mass system in SHM is given as:

$T=2\pi\sqrt{\frac{m}{k}}$

Plug in the given values and solve for period 'T'. This gives,

$T=2\pi\sqrt{\frac{1}{98}}\\T=2\pi\times 0.101\\T=0.635\ s$

Therefore, the period of oscillation is 0.635 s.

5 0

3 years ago

Kūna veikia jėga kurios momentas 0,4 N × m petys - 5 cm. Koks šios jėgos dydis?

umka21 [38]

Answer:

F = 8 N

Explanation:

The question says "The body is subjected to a force with a moment of 0.4 N × m shoulder - 5 cm. What is the magnitude of this force?

Given that,

Moment/Torque, $\tau=0.4\ N-m$

Distance moved, d = 5 cm = 0.05 m

We need to find the magnitude of this force. We know that, the torque acting on an object is given by :

$\tau=Fd\\\\F=\dfrac{\tau}{d}\\\\F=\dfrac{0.4\ N-m}{0.05\ m}\\\\F=8\ N$

So, the magnitude of force is equal to 8 N.

8 0

2 years ago

How does surface currents would be affected if eArth didn't rotate

forsale [732]

Surface ocean currents are generally wind-driven. However, the rotation of the Earth affects the way the waters move through currents. Without rotation, currents may not exist.

6 0

3 years ago

You have a friend who is entering a skateboarding competition in Los Angeles. She wants to take a running start and then jump on

ahrayia [7]

Answer

given,

mass skateboard = 5 Kg

length on the horizontal road = 2 m

maximum speed she can run= 8 m/s

mass of girl = 50 Kg

conservation of momentum

M V = (M+m)v

50 x 8 = (50 + 5)v

400 = (55)v

v = 7.27 m/s

using conservation of momentum

$m g h = \dfrac{1}{2} m v^2$

$h = \dfrac{v^2}{2g}$

$h = \dfrac{7.27^2}{2\times 9.8}$

h = 2.69 m

no, she will not be able to reach the height of 3 m

5 0

3 years ago