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Pavlova-9 [17]
3 years ago
11

Name 3 renewable energy resources

Physics
2 answers:
Ad libitum [116K]3 years ago
7 0
Solar energy, wind energy, hydro energy
babymother [125]3 years ago
3 0
Tidal power, hydroelectricity, biomass
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A wheel is rotating at a rate of 2.0 rev every 3.0s. through what angle, in radian , does the wheel rotate in 1.0s?​
igomit [66]

Answer:

4 \pi

Explanation:

First of all, let's convert 2.0 rev into radians:

1.0 rev = 2\pi rad\\2.0 rev = 4 \pi rad

This means that the angular speed of the wheel is

\omega = 2.0 rev/s = 4 \pi rad/s

The angle through which the wheel rotates in a time t is given by

\theta=\omega t

And substituting t=1.0 s, we find

\theta=(4\pi rad/s)(1.0 s)=4 \pi rad

7 0
3 years ago
The picture shows two different species of mammals that use wings to glide among tree tops. However, scientists theorize that th
AlekseyPX

Answer:

c

Explanation:

6 0
3 years ago
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The initial concentration of N2O4 is 0.45M The system is heated and allowed to reach equilibrium. At equilibrium concentration o
Damm [24]

Answer : The value of equilibrium constant K_c for the following reaction will be, 2.4

Explanation :  Given,

Initial concentration of N_2O_4 = 0.45 M

Equilibrium concentration of NO_2 = 0.30 M

K_c is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

N_2O_4(g)\rightleftharpoons 2NO_2(g)

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

Actual concentration of NO_2 at equilibrium = 2\times 0.30M=0.6M

Concentration of N_2O_4 at equilibrium = [N_2O_4]-[NO_2]=0.45-0.30=0.15M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Now put all the given values in this expression, we get :

K_c=\frac{(0.6)^2}{(0.15)}

K_c=2.4

Therefore, the value of equilibrium constant K_c for the following reaction will be, 2.4

3 0
3 years ago
The partition coefficient K in a gas chromatographic experiment can be described by: Cm Cs K = where "Cs" and "Cm" refer to the
Amiraneli [1.4K]

Explanation:

K in chromatography is defined as a partition coefficient. It is an equilibrium constant that determines the measure to which the solutes partition between  two phases.

K = Cm/Cs

where Cm is solute concentration in mobile phase

          Cs is solute concentration in stationary phase

When K is more, then it implies that the solute concentration in the mobile phase is more in chromatography test.

4 0
3 years ago
Please do parts (a) and part (b) below and include diagrams where applicable:
Harlamova29_29 [7]

Answer:

Part a)

m = 232.1 gram

Part b)

M = 928.6 gram

Explanation:

Part a)

As we know that frequency of vibration for a given spring block system is given by formula

f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}

so if it is given as 0.90 Hz then we will have

0.90Hz = \frac{1}{2\pi}\sqrt{\frac{k}{m}}

Now if additional mass is attached with it the frequency changed to 0.50 Hz

0.50 Hz = \frac{1}{2\pi}\sqrt{\frac{k}{m + 520}}

now divide two equations

\frac{0.90}{0.50} = \sqrt{\frac{m + 520}{m}}

3.24m = m + 520

m = 232.1 g

Part b)

Now the frequency is changed to 0.45 Hz

so again we will have

0.45 Hz = \frac{1}{2\pi}\sqrt{\frac{k}{M}}

again divide it with first equation above

\frac{0.90}{0.45} = \sqrt{\frac{M}{m}}

as we know that m = 232.1 g

so total mass needed for 0.45 Hz will be

M = 928.6 gram

7 0
3 years ago
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