Can someone please help me with 363?

) How many moles are there in 2.00 x 10^19 molecules of calcium phosphate?

Tamiku [17]

Answer:

$\huge 3.322 \times {10}^{ - 5} \: \: moles \\$

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{2.00 \times {10}^{19} }{6.02 \times {10}^{23} } \\ \\ = 3.322 \times {10}^{ - 5} \: \: moles$

Hope this helps you

4 0

3 years ago

Explain why alkanes can be described as hydrocarbons.

worty [1.4K]

Answer:

<h3>The International Union of Pure and Applied Chemistry (IUPAC) defines alkanes as "acyclic branched or unbranched hydrocarbons having the general formula CnH2n+2, and therefore consisting entirely of hydrogen atoms and saturated carbon atoms". ... The number of carbon atoms may be considered as the size of the alkane.</h3>

5 0

2 years ago

How do I do this? What are the answers to the 5 questions shown?

frozen [14]

Answer:

1. C₃H₆O₃

2. C₆H₁₂

3. C₆H₂₄O₆

4. C₆H₆

5. N₂O₄

Explanation:

1. Determination of the molecular formula.

Empirical formula => CH₂O

Mass of compound = 90 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₂O]ₙ = 90

[12 + (2×1) + 16]n = 90

[12 + 2 + 16]n = 90

30n = 90

Divide both side by 30

n = 90/30

n = 3

Molecular formula = [CH₂O]ₙ

Molecular formula = [CH₂O]₃

Molecular formula = C₃H₆O₃

2. Determination of the molecular formula.

Empirical formula => CH₂

Mass of compound = 84 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₂]ₙ = 84

[12 + (2×1)]n = 84

[12 + 2]n = 84

14n = 84

Divide both side by 14

n = 84/14

n = 6

Molecular formula = [CH₂]ₙ

Molecular formula = [CH₂]₆

Molecular formula = C₆H₁₂

3. Determination of the molecular formula.

Empirical formula => CH₄O

Mass of compound = 192 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₄O]ₙ = 192

[12 + (4×1) + 16]n = 192

[12 + 4 + 16]n = 192

32n = 192

Divide both side by 32

n = 192/32

n = 6

Molecular formula = [CH₄O]ₙ

Molecular formula = [CH₄O]₆

Molecular formula = C₆H₂₄O₆

4. Determination of the molecular formula.

Empirical formula => CH

Mass of compound = 78 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH]ₙ = 78

[12 + 1]n = 78

13n = 78

Divide both side by 13

n = 78/13

n = 6

Molecular formula = [CH]ₙ

Molecular formula = [CH]₆

Molecular formula = C₆H₆

5. Determination of the molecular formula.

Empirical formula => NO₂

Mass of compound = 92 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[NO₂]ₙ = 92

[14 + (2×16)]n = 92

[14 + 32]n = 92

46n = 92

Divide both side by 46

n = 92/46

n = 2

Molecular formula = [NO₂]ₙ

Molecular formula = [NO₂]₂

Molecular formula = N₂O₄

6 0

3 years ago

An atom has 14 protons, 16 neutrons, and 14 electrons. What is its mass number?

Andrews [41]

The answer is 30.

Explanation:

The total number of protons and neutrons in a nucleus is called mass number. So 14 proton plus 16 neutron is = 30 mass number.

6 0

3 years ago

What is the mass number of an atom that contains 12 protons, 14 neutrons, and 12 electrons? *

Yuri [45]

The mass number of an atom : 26

<h3>Further explanation</h3>

Given

12 protons, 14 neutrons, and 12 electrons

Required

The mass number

Solution

Inside the atom there are 3 sub-particles, namely protons, neutrons and electrons. Protons and electrons are present in the atomic nucleus while electrons move around the atomic nucleus through energy levels in the atomic shell

Atomic number = number of protons = number of electrons

Mass number = number of protons + number of neutrons

Input the value :

Mass number = 12 + 14

Mass number = 26

7 0

3 years ago