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HACTEHA [7]
3 years ago
12

Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed leave it blank. If no reaction occurs leav

e all boxes blank and click on "Submit". Use H3O+ for hydronium ion. Write a net ionic equation for the reaction that occurs when excess hydrobromic acid (aq) and zinc sulfide are combined.
Chemistry
1 answer:
Andrei [34K]3 years ago
6 0

Answer:

ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)

Explanation:

First, we will write the molecular equation, since it is easier to balance.

2 HBr(aq) + ZnS(s) ⇄ H₂S(aq) + ZnBr₂(aq)

In the full ionic equation we include all ions and molecular species.

2 H⁺(aq) + 2 Br⁻(aq) + ZnS(s) ⇄ 2 H⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + 2 Br⁻(aq)

In the net ionic equation we include only the ions that participate in the reaction and the molecular species.

ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)

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Which are characteristics of natural selection? Select three options.
Luda [366]
Affects populations,
Occurs when there is genetic variation
Selects organisms with certain traits to survive.
5 0
3 years ago
The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.
Vikki [24]

Answer :  The solubility of this compound in g/L is 565.414\times 10^{-6}g/L.

Solution : Given,

K_{sp}=2.42\times 10^{-11}

Molar mass of MnCO_3 = 114.945g/mole

The balanced equilibrium reaction is,

                      MnCO_3\rightleftharpoons Mn^{2+}+CO^{2-}_3

At equilibrium                         s       s

The expression for solubility constant is,

K_{sp}=[Mn^{2+}][CO^{2-}_3]

Now put the given values in this expression, we get

2.42\times 10^{-11}=(s)(s)\\2.42\times 10^{-11}=s^2\\s=0.4919\times 10^{-5}=4.919\times 10^{-6}moles/L

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

s=4.919\times 10^{-6}moles/L\times 114.945g/mole=565.414\times 10^{-6}g/L

Therefore, the solubility of this compound in g/L is 565.414\times 10^{-6}g/L.


8 0
3 years ago
true or false: 1. An object can have only one type of energy at a time 2. If an object has energy, it must be moving. 3. All ene
gregori [183]
True is the correct answer
4 0
3 years ago
How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space
dezoksy [38]

Answer:

1.40 atm is the pressure for the gas

Explanation:

An easy problem to solve with the Ideal Gases Law:

P . V = n . R .T

T° = 370K

V = 17.3L

n = 0.8 mol

Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K

P = (0.8mol . 0.082L.atm/mol.K . 370K) / 17.3L = 1.40 atm

7 0
3 years ago
Read 2 more answers
Balance this equation<br> _Al +_HCI --&gt; _H2 +_AICIz
kumpel [21]

2Al+6HCl⇒3H₂+2AlCl₃

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

Al+HCl⇒H₂+AlCl₃

  • Give coefficient

aAl+bHCl⇒cH₂+AlCl₃

  • Make equation

Al, left=a, right=1⇒a=1

Cl, left=b, right=3⇒b=3

H, left=b, right=2c⇒b=2c⇒3=2c⇒c=3/2

the equation becomes :

Al+3HCl⇒3/2H₂+AlCl₃ x2

2Al+6HCl⇒3H₂+2AlCl₃

5 0
3 years ago
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