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1 answer:
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Explanation:
The given data is as follows.
(NaCl) =
(H-O=C-ONO) =
(HCl) =
Conductivity of monobasic acid is
Concentration = 0.01
Therefore, molar conductivity () of monobasic acid is calculated as follows.
=
=
=
Also, =
=
=
Relation between degree of dissociation and molar conductivity is as follows.
=
= 0.1254
Whereas relation between acid dissociation constant and degree of dissociation is as follows.
K =
Putting the values into the above formula we get the following.
K =
=
=
=
Hence, the acid dissociation constant is .
Also, relation between and
is as follows.
=
= 3.7454
Therefore, value of is 3.7454.