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1 year ago

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You place a large pear on a scale and it shows a mass of 200 grams. What is the mass of that pear in centigrams? Remember: King

Henry Doesn’t Usually Drink Chocolate Milk! 2 centigrams 20,000 centigrams 2,000 centigrams 20 centigrams

1 answer:

statuscvo [17]1 year ago

7 0

Answer:

20,000 centigrams

Explanation:

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Answer:

C. 10

Explanation:

So wr for protons is 2 and wr for alpha particles is 20. In these terms, alpha particles cause ten times more damage then protons.

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Part complete When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation

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<u>Answer:</u> The isotopic symbol of barium is $_{56}^{138}\textrm{Ba}$ and that of strontium is $_{38}^{89}\textrm{Sr}$

<u>Explanation:</u>

Nuclear fission reactions are defined as the reactions in which a heavier nuclei breaks down in two or more smaller nuclei.

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

$^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Ba}+^{94}_{36}\textrm{Kr}+3^1_0\textrm{n}$

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 94 + 3

A = 139

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 36 + 0

Z = 56

The isotopic symbol of barium is $_{56}^{139}\textrm{Ba}$

For the given fission reaction:

$^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Sr}+^{143}_{54}\textrm{Xe}+3^1_0\textrm{n}$

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 143 + 3

A = 90

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 54 + 0

Z = 38

The isotopic symbol of strontium is $_{38}^{89}\textrm{Sr}$

Hence, the isotopic symbol of barium is $_{56}^{138}\textrm{Ba}$ and that of strontium is $_{38}^{89}\textrm{Sr}$

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