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joja [24]
3 years ago
6

Write the chemical name for MnS2?

Chemistry
2 answers:
DerKrebs [107]3 years ago
7 0

Answer:

Manganese(II) sulfide

Explanation:

I believe that I am correct here. It is a compound of manganese and sulfide.

Reptile [31]3 years ago
3 0

Answer:

Manganese(II) sulfide

Explanation:

is a chemical compound of manganese and sulfur. It occurs in nature as the mineral alabandite (isometric), rambergite (hexagonal), and recently found browneite (isometric, with sphalerite-type structure, extremely rare, known only from a meteorite).

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Smart people help me pass my class
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Answer:

im not smart but here

Explanation:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.

4 0
3 years ago
Balance this equation, please.
Digiron [165]

Answer:3Li+YbCl3=Yb +3LiCl

Explanation:as there are three cl in the first one so to balance them we will put 3before LiCl in order to make Cl balanced now there are 3 Li also so put before Li 3 making it also balanced Yb is balanced already

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Which has not been a major source of CFCs
ipn [44]

Answer : Any natural sources of CFC's are not known only the major sources like aerosols, propellants, refrigerants,etc are known. So, if any natural sources are given then it cannot be called as a major source for emitting CFC into environment.

4 0
3 years ago
Read 2 more answers
PLS HELP What is the mass of hydrogen atoms that is measured at 54 u?
tankabanditka [31]

The mass of hydrogen atoms that is measured at 54 u given the relationship is 89.64×10¯²⁴ g

<h3>Conversion scale </h3>

1 u = 1.66×10¯²⁴ g

<h3>How to determine the mass of hydrogen atoms </h3>
  • Mass of Hydrogen (u) = 54 u
  • Mass of Hydrogen (g) =?

1 u = 1.66×10¯²⁴ g

Therefore

54 u = 54 × 1.66×10¯²⁴ g

54 u = 89.64×10¯²⁴ g

Thus, the mass of the hydrogen atoms measured at 54 u is 89.64×10¯²⁴ g

Learn more about conversion:

brainly.com/question/2139943

#SPJ1

3 0
1 year ago
Nitrogen gas is introduced into a large deflated plastic bag. No gas is allowed to escape, but as more and more nitrogen is adde
Natalija [7]

Answer:

0.9307 moles have been introduced into the bag.

Explanation:

Pressure of the gas within the bag,P = 1.00 atm

Temperature of the gas remains at room temperature,T=20.0 °C = 293.15 K

Volume of the gas in the bag = V = 22.4 L

Number of moles of gas = n

Using an ideal gas equation:

PV=nRT

1.00 atm\times 22.4 atm=n\times 0.0821 atm l/mol K\times 293.15 K

n = 0.9307 moles

0.9307 moles have been introduced into the bag.

4 0
3 years ago
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