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erastova [34]
3 years ago
6

Derive the formula v= u+ atplease derive in detail ​

Physics
2 answers:
lesantik [10]3 years ago
7 0

Answer:

pagal hai ye

Explanation:

mark me as brainliest ❤️

gogolik [260]3 years ago
4 0

Lets do

We know

The rate of change of velocity is acceleration .

\\ \sf\longmapsto a=\dfrac{dv}{dt}

\\ \sf\longmapsto dv=adt

Integrate both sides

\\ \sf\longmapsto \int dv=a\int dt

As acceleration is constant .Take it outside of integral .On velocity we can take limit u to v and time from 0 to t

\\ \sf\longmapsto {\displaystyle{\int}}^v_u dv=a{\displaystyle{\int}}^t_0 dt

Hence

\\ \sf\longmapsto v{\huge{|}}^v_u=at

\\ \sf\longmapsto v-u=at

\\ \sf\longmapsto v=u+at

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When we kept the Earth's mass the same, but shrank its size, we saw that had an effect on its escape speed. Albert Einstein used
nadezda [96]

Answer:

Check the explanation

Explanation:

The escape velocity is the velocity needed by any object to overcome the gravitational force of the planet on which it’s present. Now we know that the gravitational force is directly proportional to the mass of the planet and inversely proportional to the distance of the object from the center of planet.

If we keep the mass of earth constant and decrease the size of the earth than this will decrease the distance between the object and the center of the earth and thus the gravitational force that will act on the body will increase substantially which will in turn increase the value of the escape velocity.

The value of escape velocity will keep on increasing as the size of the earth will shrink till it reaches to a point when the value of escape velocity becomes more than the speed of light and since it’s impossible to travel with a speed greater than the speed of light and therefore at this point it will become impossible for a spacecraft to escape the earth.

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3 years ago
A spring on Earth has a 0.500 kg mass suspended from one end and the mass is displaced by 0.3 m. What will the displacement of t
julia-pushkina [17]

To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.

The extension of the spring due to the weight of the object on Earth is 0.3m, then

F_k = F_{W,E}

kx_1 = mg

The extension of the spring due to the weight of the object on Moon is a value of x_2, then

kx_2 = mg_m

Recall that gravity on the moon is a sixth of Earth's gravity.

kx_2 = m\frac{g}{6}

kx_2 = \frac{1}{6} mg

kx_2 = \frac{1}{6} kx_1

x_2 = \frac{1}{6} x_1

We have that the displacement at the earth was x_1 = 0.3m, then

x_2 = \frac{1}{6} 0.3

x_2 = 0.05m

Therefore the displacement of the mass on the spring on Moon is 0.05m

6 0
3 years ago
Question 4 - If Angelica starts out at 30m/s, and in 16 s speeds up to 84 m/s, what is her acceleration?
Triss [41]

Answer:

C. 3.375 m/s^2

Explanation:

The acceleration of an object can be found using the equation:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time it takes for the velocity to change from u to v

In this problem:

u = 30 m/s is the initial velocity of Angelica

v = 84 m/s is the final velocity

t is the time

Substituting into the equation, we find the acceleration:

a=\frac{84-30}{16}=3.375 m/s^2

4 0
3 years ago
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