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erastova [34]
3 years ago
6

Derive the formula v= u+ atplease derive in detail ​

Physics
2 answers:
lesantik [10]3 years ago
7 0

Answer:

pagal hai ye

Explanation:

mark me as brainliest ❤️

gogolik [260]3 years ago
4 0

Lets do

We know

The rate of change of velocity is acceleration .

\\ \sf\longmapsto a=\dfrac{dv}{dt}

\\ \sf\longmapsto dv=adt

Integrate both sides

\\ \sf\longmapsto \int dv=a\int dt

As acceleration is constant .Take it outside of integral .On velocity we can take limit u to v and time from 0 to t

\\ \sf\longmapsto {\displaystyle{\int}}^v_u dv=a{\displaystyle{\int}}^t_0 dt

Hence

\\ \sf\longmapsto v{\huge{|}}^v_u=at

\\ \sf\longmapsto v-u=at

\\ \sf\longmapsto v=u+at

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Oksana_A [137]

Answer:

C

Explanation:

BECAUSE ITS GOING ON AND ON IF ITS NOT CORRECT I WILL VOTE YOU BRAINLEST ON MY QUESTION

3 0
3 years ago
A 81 kg person sits on a 3.8 kg chair. Each leg of the chair makes contact with the floor in a circle that is 1.2 cm in diameter
tankabanditka [31]

Answer:

1.9 MPa

Explanation:

Mass of person = 81 kg

Mass of chair = 3.8 kg

Diameter of contact point = 1.2 cm = D

Radius of contact point = 1.2/2 = 0.6 cm

Total mass of chair and person = 81 + 3.8 = 84.8 kg = M

Acceleration due to gravity = 9.81 m/s²

Force acting on the floor

<em>F = Mg</em>

<em>⇒F = 84.8×9.81</em>

<em>⇒F = 831.888 N</em>

Area of the contact point

<em>A = πR²</em>

<em>⇒A = π0.006²</em>

<em>⇒A = π0.000036 m²</em>

Area of the four points is

<em>4A = 0.000144π m²</em>

Pressure

p=\frac{F}{A}\\\Rightarrow p=\frac{831.888}{0.000144\pi}\\\Rightarrow p=1838876.21\ Pa=1.83887621\times 10^6\ Pa=1.9 MPa

Pressure exerted on the floor by each leg of the chair is 1.9 MPa

5 0
3 years ago
Is the part of the microscope that allows you to adjust the light?
madreJ [45]
According to funtriva.com, the piece that allows you to adjust the amount of light that's coming through the microscope is called the adjustable diaphragm. It is located under to stage (where what you are observing is placed on) and can be rotated to make the light<span> intensity change</span>
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4 years ago
Name the apparatus used to measure friction force? PLEASE HELP AS SOON AS POSSIBLE
melisa1 [442]
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8 0
3 years ago
A student evaluates a weight loss program by calculating the number of times he would need to climb a 14.0 m high flight of step
Liula [17]

Answer:

400 trips

Explanation:

Mechanical energy needed to climb 14 m by a man of 68 kg

= mgh

= 68 x 9.8 x 14

= 9330 J

1 Kg of fat releases 3.77 x 10⁷ J of energy

.45 kg of fat releases 1.6965 x 10⁷ J of energy

22% is converted into mechanical energy

so 22% of 1.6965 x 10⁷ J

= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.

one trip of climbing of 14 m requires 9330 J of mechanical energy

no of such trip possible with given mechanical energy

= 3732.3 x 10³ / 9330

= 400 trips

7 0
3 years ago
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