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erastova [34]
2 years ago
6

Derive the formula v= u+ atplease derive in detail ​

Physics
2 answers:
lesantik [10]2 years ago
7 0

Answer:

pagal hai ye

Explanation:

mark me as brainliest ❤️

gogolik [260]2 years ago
4 0

Lets do

We know

The rate of change of velocity is acceleration .

\\ \sf\longmapsto a=\dfrac{dv}{dt}

\\ \sf\longmapsto dv=adt

Integrate both sides

\\ \sf\longmapsto \int dv=a\int dt

As acceleration is constant .Take it outside of integral .On velocity we can take limit u to v and time from 0 to t

\\ \sf\longmapsto {\displaystyle{\int}}^v_u dv=a{\displaystyle{\int}}^t_0 dt

Hence

\\ \sf\longmapsto v{\huge{|}}^v_u=at

\\ \sf\longmapsto v-u=at

\\ \sf\longmapsto v=u+at

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Explanation:

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3 years ago
The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s. The centripetal acceleration of the
Marat540 [252]

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<u>Given the following data;</u>

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Centripetal acceleration is given by the formula;

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5 0
3 years ago
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In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 100 cm. What is the phas
Anni [7]

Answer:

The phase difference is  \Delta \phi  = 180^o

Explanation:

From the question we are told that

     The distance between the slits is d = 0.2 \ mm = \frac{0.2}{1000}  = 0.2 *10^{-3} \ m

     The distance to the screen is D = 100 cm = \frac{100}{100} = 1 \ m

      The wavelength is  \lambda = 400nm

 The distance of the wave from the  central maximum is L =  5mm = 5*10^{-3} m

   

Generally the path difference of this  waves is mathematically represented as

              y = d sin \theta

Here \theta is the angle between the the line connecting the mid-point of the slits with  the screen and the line  connecting the mid-point of the slits to the central maximum

  This implies that

              tan \theta  = \frac{L}{D}

     =>     \theta = tan ^{-1} \frac{L}{D}

             \theta = tan ^{-1} [\frac{5*10^{-3}}{1}]

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Substituting values into the formula for path difference

       y = 0.2 *10^{-3} sin(0.2864)  

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The phase difference is mathematically represented as

          \Delta \phi = \frac{2 \pi }{\lambda }  * y

Substituting values        

         \Delta \phi = \frac{2 \pi }{400 *10^{-9} }  \ * 9.997*10^{-7}

         \Delta \phi =5 \pi

Converting to degree

         \Delta \phi =5 \pi radians = 5 (180^o)  =  180^o  

the solution is subtracted by 360° in order to get the actual angle

 

             

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