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kari74 [83]
3 years ago
15

Find the resistance of a wire of length 0.65m, 0.2mm and resistivity 3X10^-6 ohm metre.​

Physics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

hope this is help full

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Answer:

1.school and community helps in growth and development of you social health as when u learn how to be compatible with the people around you, you will do better in life

2. by trying and solving

by not giving

by innovating

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BY KNOWING THAT U CAN DO IT

7 0
2 years ago
Due Ma<br> duart<br> ded<br> out<br> 25 N<br> 35 N<br> 1-03
Anuta_ua [19.1K]

Answer:

what's that all about

hehehwhe

Explanation:

dgbjjjedgkigdssfhkkoyddwrhkoyeqaxghjjhasghffhjiopjtewqetujjgda

8 0
3 years ago
Question 9
Ilya [14]
True ! Attending the funeral of a foreign leader IS fulfilling the role of head of state.
5 0
3 years ago
An unmarked police car traveling a constant 95 km/h is passed by a speeder. Precisely 1.00 s after the speeder passes, the polic
Montano1993 [528]

Answer:

Speed of the speeder will be 28 m/sec

Explanation:

In first case police car is traveling with a speed of 90 km/hr

We can change 90 km/hr in m/sec

So 90km/hr=\frac{90\times 1000m}{3600sec}=25m/sec

Car is traveling for 1 sec with a constant speed so distance traveled in 1 sec = 25×1 = 25 m

After that car is accelerating with a=2m/sec^2 for 7 sec

So distance traveled by car in these 7 sec

S=ut+\frac{1}{2}at^2=25\times 7+\frac{1}{2}\times 2\times 7^2=224m

So total distance traveled by police car = 224 m

This distance is also same for speeder

Now let speeder is moving with constant velocity v

so 224=\left ( 1+7 \right )v

v = 28 m/sec

4 0
3 years ago
Read 2 more answers
A furlong is an old british unit of length equal to 0.125 mi, derived from the length of a furrow in an acre of ploughed land. a
castortr0y [4]

The speed of light is: c = 3x10^8 m/s <span>

or 

c = 186,000,000 miles/sec = 1.86x10^8 mi/s 

1 furlong = 0.125 mile 

1 fortnight = 2 weeks(7d/wk)(24h/d)(3600s/h) 
= 1209600s = 1.2096x10^6 s 

Therefore, 

c =1.86x10^8 mi/s(1furl/0.125mi)(1.2096x10^6s/fort) 

<span>c = 18x10^14 furlong/fortnight = 18x10^8 Mfurlong/fortnight</span></span>

4 0
3 years ago
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