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kari74 [83]
3 years ago
15

Find the resistance of a wire of length 0.65m, 0.2mm and resistivity 3X10^-6 ohm metre.​

Physics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

hope this is help full

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A 5.00-kg ball is hanging from a long but very light flexible wire when it is struck by a 1.50-kg stone traveling horizontally t
devlian [24]

consider the right direction as positive and left direction as negative.

M = mass of the ball = 5 kg

m = mass of stone = 1.50 kg

V_{bi} = initial velocity of the ball before collision = 0 m/s

V_{si} = initial velocity of the stone before collision = 12 m/s

V_{bf} = final velocity of the ball after collision = ?

V_{sf} = final velocity of the stone after collision = - 8.50 m/s

using conservation of momentum

MV_{bi} + mV_{si} = MV_{bf} + mV_{sf}

(5) (0) + (1.5) (12) = 5 V_{bf} + (1.50) (- 8.50)

V_{bf} = 6.15 m/s

h = height gained by the ball

using conservation of energy

Potential energy gained by ball at Top = kinetic energy at the bottom

Mgh = (0.5) MV_{bf}^{2}

(9.8) h = (0.5) (6.15)²

h = 1.93 m

8 0
3 years ago
Read 2 more answers
The Sun radiates energy at a rate of about 4×1026W. Earth is about 150×106km from the Sun.
sergiy2304 [10]

The average intensity received on the Earth's surface is 12.6*10^{10} W/m^{2}

​Intensity = Rate  of  energy radiated/4\pi R^{2}

where  R is the distance of the earth from the sun.

I=4*10^{26}/4\pi *[150*106*10^{3}]^{2}

I=0.12597*10^{12}

I=12.6*10^{10} W/m^{2}

What is the meaning of the intensity of sunlight?

Sun intensity refers to the amount of incoming solar energy, or radiation, that reaches the Earth's surface. The angle at which the rays from the sun hit the Earth determines this intensity.

What is the average intensity received on the Earth's surface?

The average intensity received on the Earth's surface is given by:

I=rate of energy radiated/4\pi R^{2}

Thus, the average intensity received on the Earth's surface is 12.6*10^{10} W/m^{2}

To know more about the intensity received from the sun:

brainly.com/question/29579262

#SPJ1

8 0
1 year ago
The tallest volcano on Mars
Nonamiya [84]

Answer: Is three times the height of Mt. Everest

Explanation:

Using the process of elimination we can rule out “D” Because its a volcano, C because it says we have visited mars 44 times not the volcano, B because in the passage is literally says “3 times the size of Mt. Everest”.

8 0
3 years ago
Read 2 more answers
If the San Andreas Fault moves 200 cm (2 meters) per big earthquake, and plate movement is xx cm/yr (see question above), how ma
weqwewe [10]

Answer:

Option C

80 years

Explanation:

<em>From Scientific records, the rate of movement of the plate is 0.025 meters</em>

Since the fault moves at the rate of 2 meters per year, to obtain the number of years it will takes to produce an earth quake, we will have to divide the rate of movement of the fault by the rate of movement of the plate.

Number of years for earthquake = \frac{2}{0.025}= 80 years.

Hence, it will take 80 years to produce one big earthquake.

5 0
4 years ago
What might happen to the mass and/or the distance between two objects to increase the gravitational force of attraction?
goldfiish [28.3K]
The gravitational force may grow weaker if separation occurs with the distance.

hope i helped :)
6 0
3 years ago
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