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AlladinOne [14]
3 years ago
8

What property is not used to separate a mixture ?

Chemistry
1 answer:
Goshia [24]3 years ago
7 0

Answer:

Conductivity

Explanation:

You might be interested in
When 69.9 g heptane is burned it releases __ mol water.
professor190 [17]

Answer:

1) When 69.9 g heptane is burned it releases 5.6 mol water.  

2) C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.

Explanation:

  • Firstly, we should balance the equation of heptane combustion.
  • The balanced equation is: <em>C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.</em>

This means that every 1.0 mole of complete combustion of heptane will release 8 moles of H₂O.

  • We need to calculate the no. of moles in 69.9 g of heptane that is burned using the relation: <em>n = mass/molar mass.</em>

n of 69.9 g of heptane = mass/molar mass = (69.9 g)/(100.21 g/mol) = 0.697 mol ≅ 0.7 mol.

<em><u>Using cross multiplication:</u></em>

1.0 mol of heptane releases → 8 moles of water.

0.7 mol of heptane releases → ??? moles of water.

<em>∴ The no. of moles of water that will be released from burning (69.9 g) of water</em> = (0.7 mol)(8.0 mol)/(1.0 mol) = <em>5.6 mol.</em>

<em>∴ When 69.9 g heptane is burned it releases </em><em>5.6</em><em> mol water. </em>

<em />

5 0
3 years ago
A gas mixture with a total pressure of 750 mmHg contains each of the following gases at the indicated partial pressures: CO2 , 1
jolli1 [7]

Answer: a) 211 mm Hg

b) 0.629 grams

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2+p_3+p_4

p_{total} = total pressure = 750 mmHg

p_{CO_2} = 124 mm Hg

p_{Ar} = 218 mm Hg

p_{O_2} = 197 mm Hg

p_{He} = ?

750 mmHg=124 mm Hg+218 mm Hg+197 mm Hg+p_{He}

p_{He}=211mmHg

Thus  the partial pressure of the helium gas is 211 mmHg.

b) According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 211 mmHg = 0.28 atm   (760mmHg=1atm)

V= Volume of the gas = 13.0 L

T= Temperature of the gas =  282 K  

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= ?

n=\frac{PV}{RT}=\frac{0.28\times 13.0}0.0821\times 282}=0.157moles

Mass of helium= moles\times {\text {molar mass}}=0.157\times 4=0.629g

Thus mass of helium gas present in a 13.0-L sample of this mixture at 282 K is 0.629 grams

8 0
4 years ago
Which of the following is the correct definition of chemical energy?
bulgar [2K]

A, energy stored in chemical bonds of molecules, is correct because chemical energy is the potential energy in the molecule, for example the chemical energy in coal is converted to electrical energy through power plants. The energy was already stored in the coal, just in a different form.

7 0
3 years ago
. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r
Tom [10]

Answer :  The energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

Explanation : Given,

Wavelength = 435.8nm=435.8\times 10^{-9}m

conversion used : 1nm=10^{-9}m

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength = 435.8\times 10^{-9}m

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}

E=4.56\times 10^{-19}J

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

3 0
4 years ago
An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0100 M O2. At this temperature, Kc
Naya [18.7K]
The correct answer to this question is letter "B) 8.4 × 10-4 M."

2CO+O2<->2CO2

-x       -x        +x

It started as 2CO2 so +x, then it decomposed into 2CO and O2, so-x

2CO-oxidized, O2-Oxidized, 2CO2-reduced


the easiest way is to look at the equation, so if we have some reactant and no product 

A<->2C+D

-x    +2x +x
so if we had product concentration, and no reactant concentration 3A<-> C+D +3x -x-x <span>
</span>
8 0
4 years ago
Read 2 more answers
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