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nikklg [1K]
2 years ago
10

I need help with Hess law

Chemistry
1 answer:
ICE Princess25 [194]2 years ago
6 0

Answer:

alright

Explanation:

Hess law is  the enthalpy change for a reaction that is carried out in a series of steps is equal to the sum of the enthalpy changes for the individual steps. Consistent with the law of conservation of energy. Starting and final conditions must be the same.

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One end has a specific binding site for a particular amino acid and the other end
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7. This part of the brain controls memory, and long term abuse of marijuana can permanently
eduard

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molecules of i2 are produced by the reaction of 0.4321 mol of cucl2 according to the following equation. 2 cucl2 4 ki → 2 cui 4
Juli2301 [7.4K]

\: 1.237 \times 10^{23}   molecules \: of \:I _{2} \: are

are\: produced \: and \: 53.74 \: g \: of \: I _{2} \: are

produced from the reaction.

The overall balanced equation for the reaction is,

2CuCl_{2} +   KI→2CuI + 4KCl  + I_{2}

Number  \: of  \: moles  \: ofCuCl_{2}=0.4235 \: mol

2 \: moles \: of \: CuCl_{2} \: produce \: \: 1 \: mole \:

of \:  I_{2}.

2 \: mole \: of \: CuCl_{2}  = 1 \: mole \: of \:  I_{2}

1 \: mole \: of \: I_{2} \:  = 6.022 \times 10 ^{23}  \: molecules \: of  I_{2}

So, the number of molecules produced in the reaction of

I_{2} \: are

=  \frac{0.4235 \times 6.022 \times 10 ^{23} }{2 }

= 1.237 \times 10^{23}  \: molecules \:

1.237 \times 10^{23}  \: molecules \: of \: I_{2} \: are \:

produced from the reaction.

Mass  \: of \:   I _{2} \: produced \: are \: is ,

=  \frac{0.4235 \times 253.8}{2}

= 53.74 \: g

53.74 \: g \: of \:  I _{2} \: produced \: in \: the \:

reaction.

Therefore , \: 1.237 \times 10^{23}   molecules

of  \: I_{2} \: are\: produced \: and \: 53.74 \: g \: of

are produced in the reaction.

To know more about moles, refer to the below link:

brainly.com/question/26416088

#SPJ4

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