Answer: v = 20 m/s
Explanation: Solution:
Use the formula of Kinetic Energy and derive for v:
KE = 1/2 mv²
To find v:
v = √ 2 KE / m
= √ 2 ( 100000 J ) / 500 kg
= √ 400 m/s
= 20 m/s
An opera singer breaks a thin glass with only the use of her high frequency voice
The duration of time for which an object stays in air is called the hang time.
For an athlete who moves 3m horizontally during a 1.25m high jump, the hang time will be the sum of the time taken by the athlete to reach the maximum height and the time taken for the athlete to reach the ground from maximum height.
Calculate the time taken t_1 by the athlete to reach the maximum height



The athlete takes same time to reach the ground from the maximum height, so 
Calculate the hang time will be



Therefore the hang time of the athlete when he moves a horizontal distance of 3m is 1s.
Similarly, when the athlete runs 6m horizontally, then also there will not be a change in the hang time of the athlete as the hang time is independent of the horizontal distance covered.
Answer:
70 W
Explanation:
Power = work / time
P = mgh / t
P = (80 kg) (9.8 m/s²) (3000 m) / (36000 s)
P = 65.3 W
Rounding to one significant figure, the average power output is 70 W.
Answer:
d) Agility
Explanation:
Agility is defined as the capability or ability of the body to change the position of the body efficiently, and it requires the isolated movement's integration skills by using a combination of speed, balance, reflexes, coordination, strength, and endurance.
In the field of sport, it is categorized in a unique sport because it is a combination of various factors.
Therefore, agility is a component that is related to skill-related physical fitness.