Using safe research practices would be a very good common-sense practice in a lab environment.
Answer
given,
mass of crate = 32.5 Kg
horizontal force = 14 N
initial speed, u = 0 m/s
a) acceleration produced = ?
we know,
F = m a


a = 0.431 m/s²
b) using equation of motion
t = 10 s


s = 21.54 m
c) again using equation of motion
v = u + at
v = 0 + 0.431 x 10
v = 4.31 m/s
I’m almost certain it’s C
Answer:
h= 46.66 m
Explanation:
Given that
Initial speed of the car ,u = 110 km/h
We know that
1 km/h= 0.277 m/s
u= 30.55 m/s
lets height gain by car is h.
The final speed of the car will be zero at height h.
v²=u²- 2 g h
v= 0 m/s
0²=30.55²- 2 x 10 x h ( g = 10 m/s²)
h= 46.66 m
the answer is rust so the answer is rust