Two commonly used units<span> to measure air pressure are Inches of Mercury and </span>Millibars.<span> </span>
Ionization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>
Temperature does not change, remains 264 K
<h3>Further explanation</h3>
Given
V₁= 1.2 L
P₁ = 1.8 atm
T₁ = 264
Required
The new temperature
Solution
The volume was doubled = 2V₁ = 2 x 1.2 = 2.4 L(V2)
The pressure was halved = 0.5P₁ = 0.5 x 1.8 = 0.9 atm(P2)
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
Answer:
answer is gold
Explanation:
bcz gold is having a property of malleable so it can be drawn into thin sheets
Answer:
4 Sb (+3) + 2 Br (2) O (3) ----> 4 SbBr + 3 O(-2)
In the equation, place the valences in parentheses and the stoichiometric balance numbers so that the reaction is balanced, place them in bold.
Explanation:
In this chemical equation it seems to me that the valences of BrO are wrong.
That is why I will complete the equation, demonstrating the chemical reaction, and also use the appropriate valences.
Assuming that Sb has a valence of +3 and that the Br that appears in the form of oxide with oxygen (valence -2) has a valence of +3 (because -3 does not exist as valence or oxidation state of bromine).