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shusha [124]
2 years ago
7

Anybody who wants to ta lk can come to me.

Chemistry
1 answer:
dimaraw [331]2 years ago
7 0

Answer:

Ye, whats up bro?

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Something that an animal does that is driven by instinct is called a??
Lunna [17]

Answer:

2. Behavioral Adaption

Explanation:

I know about this, I think this is the answer. Try it out!!

5 0
2 years ago
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Why is potassium less reactive than silver
Reika [66]
Because potassium is a gas that can evolve
3 0
3 years ago
A balanced chemical equation is shown below
IrinaVladis [17]

Answer:

The answer is A.

Explanation:

C6H12O6 + 6O2 -> 6CO2 + 6H20

C6H12O6 + 6O2 -> 6CO2 + 6H20At the reactant side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

atoms, 12 hydrogen atoms and 18 oxygen atoms.At product side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

(In a balanced equation, the no. of atoms on the reactant side must be <em><u>e</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>l</u></em><em> </em>to the no. of atoms on the product side)

4 0
3 years ago
How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?
docker41 [41]

Answer:

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

Initial temperature = 52.0 °C

Final temperature = 91.5 °C

Specific heat of aluminium = 0.900 J/g°C

Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

We need 3910.5 joules of energy

6 0
3 years ago
The combustion of ethane ( C 2 H 6 ) (C2H6) produces carbon dioxide and steam. 2 C 2 H 6 ( g ) + 7 O 2 ( g ) ⟶ 4 CO 2 ( g ) + 6
REY [17]

Answer:

There is a production of 11.6 moles of CO₂

Explanation:

The reaction is this:

2C₂H₆(g)  +  7O₂(g)  ⟶  4CO₂(g)  +  6H₂O(g)

2 moles of ethane reacts with 7 moles of oxygen, to make 4 mol of dioxide and 6 moles of water vapor.

If the oxygen is in excess, we make the calculate with the ethane (limiting reactant)

2 moles of ethane produce 4 moles of dioxide

5.8 moles of ethane produce (5.8  .4)/2 = 11.6 moles

5 0
3 years ago
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