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Lady bird [3.3K]
3 years ago
6

I did questions 2 and 3 but I don't know if they are right. Someone help!

Physics
2 answers:
Tems11 [23]3 years ago
8 0

You got it right my friend

Alex73 [517]3 years ago
8 0
Yes they are correct
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What happens if you move a bar magnet back and forth along the axis of the
nadezda [96]

C) A current is induced in the coiled wire, which lights the light bulb

The moving magnetic field creates electricity which lights the light bulb

Hope it helps!

8 0
2 years ago
Read 2 more answers
Given that 1 pound is equal to 4.45 newton’s what is the weight of a 500N child in pounds?
Bond [772]

Answer:

112.36 pounds

Explanation:

Since 1 pound = 4.45 Newtons, a 500N child in pounds = 500÷4.45 = 112.36 pounds (approximately).

4 0
3 years ago
If 2 grams of element X combine with 4 grams of element Y to form compound XY, how many grams of element Y would combine with 11
kykrilka [37]
This is sort of simple.  2 grams of X can combine with 4 grams of Y to form XY.  Y is 2 times the amount of grams in X.  So if there are 11 grams of X there are 22 grams of Y to form XY.  Or you could take 11 divided by 2 is 5.5 and then multiply 4 by 5.5 to get 22.  If this is wrong please tell me I would be very happy to know.
3 0
3 years ago
A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. If your push was directed at an angle
emmasim [6.3K]

<u>Given data:</u>

m= 50 Kg,

W= m×g = 50 × 9.81 = 490.5 N

ramp angle (α) = 30 degrees,

coefficient of friction (μs) = 0.5773,

Push at an angle (Θ) = 40 degrees,

Determine: Push to get box move up (P)=?

From the figure,

Resolving the forces along the plane

W sinα + μs.R = P cos Θ       --------------------- (i)

Resolving the forces perpendicular to the inclined plane

W cosα = R+Psin Θ  =>  R= W cosα - Psin Θ -------------- (ii)

Solving (i) and (ii) and keeping <em>μs = tan Φ, Φ = Θ </em>

<em>Pmin = W sin( α +Θ  )</em>

<em>          = W[ sin α.Cos Θ + cos α.sin Θ]</em>

<em>           = 490.5 [ (sin 30.cos40) + (cos30.sin 40)]</em>

<em>           = 460.9 N</em>

<em>Minimum push required to move the box up the ramp is 460.9 N</em>


7 0
3 years ago
1. What charge is stored in a 180.0-μFcapacitor when 120.0 V is applied to it?
marin [14]

Answer:

So capacitance is charge divided by voltage and we can multiply both sides by V to solve for Q. So Q—the charge stored in the capacitor—is the capacitance multiplied by the voltage. So it's 180 times 10 to the minus 6 farads times 120 volts which is 0.0216 coulombs.

Explanation:

3 0
2 years ago
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