Answer:
The velocity of the other fragment immediately following the explosion is v .
Explanation:
Given :
Mass of original shell , m .
Velocity of shell , + v .
Now , the particle explodes into two half parts , i.e .
Since , no eternal force is applied in the particle .
Therefore , its momentum will be conserved .
So , Final momentum = Initial momentum
The velocity of the other fragment immediately following the explosion is v .
Answer:
The value is
Explanation:
From the question we are told that
The amount of power delivered is
The time taken is
The wavelength is
Generally the energy delivered is mathematically represented as
Where is the Planck's constant with value
c is the speed of light with value
So
=>
At the top of the height, the velocity is zero and acceleration is negative of acceleration due to gravity ( i.e ).
The time of the ball in air is 3.2 s, so ascending time is .
Therefore from kinematic equation,
Substituting the values we get,
, Here v = 0 at top.
Now from equation,
, here h is the height .
So,
.
Thus, the ball reached at its maximum height of 12.48 m.