Velocity of submarine A is vs = 11.0m/s
frequency emitted by submarine A. F = 55.273 × 10∧3HZ
Velocity of submarine B = vO = 3.00m/s
The given equation is
f' = ((V + vO) ((v - vS)) × f
The observer on submarine detects the frequency f'.
The sign of vO should be positive as the observer of submarine B is moving away from the source of submarine A.
The speed of the sound used in seawater is 1533m/s
The frequency which is detected by submarine B is
fo = fs (V -vO/ v +vs)
= 53.273 × 10∧3hz) ((1533 m/s - 4.5 m/s)/ (1533 m/s +11 m/s)
fo = 5408 HZ
The answer should be A.
Mountain formations tend to take thousands of years to form, lava rolls relatively slowly, and lightning can travel faster than rockets.
Hope this helped!
To solve this problem it is necessary to apply the concepts related to the condition of path difference for destructive interference between the two reflected waves from the top and bottom of a surface.
Mathematically this expression can be described under the equation

Where
n = Refractive index
t = Thickness
In terms of the wavelength the path difference of the reflected waves can be described as

Where
\lambda = Wavelenght
Equation the two equations we have that


Our values are given as
Wavelength of light



Therefore the minimum thickness of the oil for destructive interference to occur is approximately 34.0 nm