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dimaraw [331]
3 years ago
10

Explain why by referring to the kinetic particles theory PLZ HELP:(

Chemistry
1 answer:
Olegator [25]3 years ago
5 0

Answer:All matter consists of small particles which are in a continual state of motion

Explanation

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Help in my exam plzz now​
swat32

Answer:

yes your answer is correct

I hope it helps mate

I will always help you understanding your assingments have a great day

#Captainpower:)

8 0
3 years ago
How do you figure out sub shells please i need help
Tanya [424]
For any given shell the number of subshells can be found by l = n -1. This means that for n = 1, the first shell, there is only l = 1-1 = 0 subshells.
3 0
3 years ago
Calculate the energy per photon (in J) associated with a frequency of 1260 kHz. Submit answer in scientific notation using the f
aniked [119]

Taking into account the definition of photon and energy of a photon, the energy per photon is 8.3538×10⁻³⁸ J.

<h3>Energy of a photon</h3>

Electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absortion, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression:

E=h×f

where:

  • E is the energy of a photon.
  • h is the Planck's constant h.
  • f is the frequency of electromagnetic radiation.

<h3>Energy per photon</h3>

In this case, you know:

  • h=  6.63*10⁻³⁴ Js
  • f= 1260 kHz= 1,260,000 Hz= 1.26×10⁶ Hz (being 1 kHz=1000 Hz)

Replacing in the definition of energy of a photon:

E= 1.26×10⁶ Hz× 6.63×10⁻³⁴ Js

<u><em>E= 8.3538×10⁻³⁸ J</em></u>

Finally, the energy per photon is 8.3538×10⁻³⁸ J.

Learn more about energy of a photon:

brainly.com/question/8924116

brainly.com/question/6945706

brainly.com/question/8000078

#SPJ1

6 0
2 years ago
What is the molarity of an intravenous glucose solution prepared from 108 g of glucose in 2.0 L of solution? 0.018 mol/L 0.30 mo
scZoUnD [109]

Answer:

0.30 mol/L

Explanation:

Mass = 108 g

Molar mass of glucose = 180.156 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{108\ g}{180.156\ g/mol}

Moles= 0.5995\ mol

Given Volume = 2 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.5995}{2}

<u>Molarity = 0.3 mol/L</u>

7 0
3 years ago
Question 14 (5 points)
natita [175]
2 amu atomic mass units, a scale based on carbon 12
7 0
3 years ago
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