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2 years ago

Solve 2x+8<10 or 2x+8>20

Mathematics

1 answer:

galben [10]2 years ago

8 0

Answer:

1 Add 88 to both sides.

2x=10+8

2 Simplify 10+810+8 to 1818.

2x=18

3 Divide both sides by 22.

x=\frac{18}{2}

4 Simplify \frac{18}{2}

to 99.

x=9

Step-by-step explanation:

2x−8=10

1 Let x=9x=9.

2\times 9-8=10

2×9−8=10

2 Simplify 2\times 92×9 to 1818.

18-8=10

18−8=10

3 Simplify 18-818−8 to 1010.

10=10

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3 years ago

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3 years ago

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3 years ago

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Step2247 [10]

Explanation:

First we consider ΔABC and ΔBCD,

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So, ΔABC ≈ ΔBCD (By AA similarity rule )

So by taking corresponding sides in ratios we get

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Now

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Similarly,

We consider ΔABD and ΔABC

∠A=∠A (Commom)

∠B=∠D= $90\textdegree$

So,

ΔABD ≈ ΔABC (By AA similarity rule )

So by taking corresponding sides in ratios we get

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By Adding both the equation we get

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Hence, we proved the pythagorean theorem by using similarity of triangle.

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3 years ago