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slava [35]
3 years ago
9

4 cm3 cmx cmarea = 19 cm2​

Mathematics
2 answers:
statuscvo [17]3 years ago
8 0

Answer:

brbtbrbjrffkfkfkrktkrjj4j4b5b5b5bbtbtvthttht

Yakvenalex [24]3 years ago
3 0
4x3xS=19
12S=19

X=1.58333
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On a 20 sided dice what is the probability that a 11 was rolled?
Sedbober [7]

Given:

A 20 sided dice is rolled.

To find:

The probability of getting 11.

Solution:

A 20 sided dice is rolled.

On a 20 sided dice, the possible outputs are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20.

Total number of outcomes = 20

Favorable outcomes or number of 11 = 1

Now,

\text{Probability of getting 11}=\dfrac{\text{Favorable outcomes}}{\text{Total number of outcomes}}

\text{Probability of getting 11}=\dfrac{1}{20}

\text{Probability of getting 11}=0.05

Therefore, the probability of getting 11 is 0.05.

3 0
3 years ago
The sides of a rectangle are x cm and 4 cm. Its<br>perimeter is 46 cm. Determine the value of x.​
Vedmedyk [2.9K]

Answer:

x = 19 cm

Step-by-step explanation:

perimeter = 46 = 2(x + 4)

2x + 8 = 46

2x = 38

x = 19

4 0
3 years ago
Which of the following is true about the solution to h - 9 = 1?
Fed [463]
The solution must be larger than 9, because the answer is h=10
8 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
3 years ago
Show work to above problem
Len [333]
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad&#10;\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}&#10;\\\\\\&#10;|a|\implies &#10;\begin{cases}&#10;+a\\&#10;-a&#10;\end{cases}\implies \pm a\\\\&#10;-------------------------------\\\\&#10;(16x^2)^{\frac{1}{2}}\implies \pm\sqrt[2]{(16x^2)^1}\implies \pm\sqrt{4^2x^2}\implies \pm\sqrt{(4x)^2}\implies \pm 4x&#10;\\\\\\&#10;\begin{cases}&#10;+4\\&#10;-4&#10;\end{cases}\implies |4x|
5 0
3 years ago
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