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telo118 [61]
3 years ago
7

Please help .....................

Chemistry
1 answer:
Advocard [28]3 years ago
8 0

Answer:

Explanation:

The photo is not there :o

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Earth is currently 150 million km away from the Sun. If Earth was 200 million km away from the Sun, why would it no longer be ab
timurjin [86]

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The temperature would be too cold

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3 years ago
Which of the following is the correct scientific notation for 0.00000862?
Molodets [167]
862^-10 my friend this is the answer
3 0
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Are inic bonds formed when electrons are equally or unequally shared
lisabon 2012 [21]

The electrons are unequally shared. The electronegative element receives the electrons from the electropositive one.

8 0
3 years ago
Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)
Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

6 0
3 years ago
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