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Georgia [21]
3 years ago
15

What is the distance covered by a freely falling object 6 seconds after being dropped? After 10 seconds?

Physics
1 answer:
Monica [59]3 years ago
5 0

Answer:

Distance s=ut+1/2 at^2

If it’s released then this becomes

s=1/2at^2

s=1/2 *9.81*9

s=44.1 m

Explanation:

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Which statements accurately describe mass? Check all that apply. Mass is a chemical property of an object. Mass is measured usin
Sati [7]
-- Mass can be measured using a balance.
(It's not the only way.)

-- The mass of an object remains constant,
no matter where it is or what it weighs.

-- The "kilogram" is the international standard unit of mass.
A kilogram of mass weighs about 5.8 ounces on the moon,
about 13.3 ounces on Mars, about 2.2 pounds on Earth . . . . .
8 0
4 years ago
Read 2 more answers
A 1000-kilogram truck accelerates uniformly from rest, reaching a speed of 50 meters per second in 10 seconds. During the 10 sec
Nata [24]

Answer:

250 m

Explanation:

1. First, we have to calculate the acceleration:

\boxed{\mathsf{v=v_o+a\cdot t}}

where:

v = present velocity

vo = initial velocity

a = acceleration

t = time

2. Let us use given information and substitute in the expression above. Hence:

\mathsf{50=0+a\cdot10}\\\\\mathsf{50=10\cdot a}\\\\\mathsf{a=\dfrac{50}{10}}\\\\\therefore \boxed{\mathsf{a=5\,m/s^2}}}

3. Now we can calculate traveled distance with <u>Torricelli's equation</u>:

\boxed{\mathsf{v^2=v_o^2+2\cdot a \cdot d}}

where:

v = present velocity

vo = initial velocity

a = accelerarion

d = distance

4. So, we get:

\mathsf{50^2=0^2+2\cdot 5 \cdot d}\\\\\mathsf{2500=10\cdot d}\\\\\mathsf{d=\dfrac{2500}{10}}\\\\\therefore \boxed{\mathsf{d=250\,m}}

<u>Conclusion</u>: during 10 seconds the truck has traveled a distance of 250 m.

Have a nice day! : )

8 0
4 years ago
6. When sodium and oxygen react to form an ionic compound, the mass of the compound ____ the sum of the masses of the individual
arsen [322]
Because there’s no elemental degradation, the mass of the compound EQUALS the sum of the masses.
3 0
3 years ago
Which of the given will facilitate a normal Diels–Alder reaction?
babymother [125]

Answer:

D

Explanation:

-  The rate of the Diels-Alder is orders of magnitude faster if there is an electron-withdrawing group on the dienophile. For example, replacing a hydrogen on ethene with the electron-withdrawing group CN results in about a 10^5 increase in the reaction rate.

- Other common electron withdrawing functional groups that will accelerate the Diels Alder reaction of dienophiles include aldehydes, ketones, and esters.

- In short, any functional group conjugated with the pi bond which can act as a pi acceptor will accelerate a Diels-Alder reaction with a typical diene.

- See attachment for graphical explanation.

7 0
4 years ago
It is known that the population mean for the verbal section of the SAT is 500 with a standard deviation of 100. In 2006, a sampl
kvasek [131]

Answer

given,

SAT is 500 with a standard deviation of 100.

a sample of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511.

sample mean = \dfrac{standard\ deviation}{\sqrt{n}}

                      = \dfrac{100}{\sqrt{400}}

                      = 5

95% confidence level is achieved within +/- 1.960 standard deviations.

1.960 standard deviations  x  5 is equal to +/- 9.8

confidence interval = 511 - 9.8   ---  511 + 9.8

                                = 501.2-----520.8

4 0
3 years ago
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