Answer: hello the diagram related to your question is missing please the third image is the missing part of the question
Fx = 977.76 Ib/ft
Explanation:
<u>Estimate the force that water exerts on the pier </u>
V = 12 ft/s
D( diameter ) = 6 ft
first express the force on the first half of the cylinder as
Fx1 = -
---------------- ( 1 )
where ; Fy = 0
Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β ) ------------- ( 2 )
Input equation (2) into equation ( 1 ) (note : assuming Po = 0 )
attached below is the remaining part of the solution
Directing, ordering, or controlling
Answer:
576.21kJ
Explanation:
#We know that:
The balance mass 
so, 

#Also, given the properties of water as;

#We assume constant properties for the steam at average temperatures:
#Replace known values in the equation above;
#Using the mass and energy balance relations;

#We have
: we replace the known values in the equation as;

#Hence,the amount of heat transferred when the steam temperature reaches 500°C is 576.21kJ
Answer:
w = 10.437 kips
deflection at 1/4 span 20.83\E ft
at mid span = 1.23\E ft
shear stress 7.3629 psi
Explanation:
area of cross section = 18*76
length of span = 32 ft
moment = 334 kips-ft
we know that
moment = load *eccentricity
334 = w * 32
w = 10.437 kips
deflection at 1/4 span



= 20.83\E ft
at mid span



shear stress
