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miskamm [114]
4 years ago
11

How many grams of nano3 are needed to prepare 100 grams of a 15.0 % by mass nano3 solution? will give brainliest

Chemistry
1 answer:
Greeley [361]4 years ago
5 0

Answer:

Calculate the mass percent of a potassium nitrate solution when 15.0 g KNO3 is dissolved in 250 g

of water.

2. Calculate the mass percent of a sodium nitrate solution when 150.0 g NaNO3 is dissolved in 500 mL

of water. Hint: 1 mL water = 1 g water

3. Calculate the weight of table salt needed to make 670 grams of a 4.00% solution.

4. How many grams of solute are in 2,200 grams of a 7.00% solution?

5. How many grams of sodium chloride are needed to prepare 6,000 grams of a 20% solution?

Mass Percent = Grams of Solute

Grams of Solution X 100%

100%

Grams of Solute = Grams of Solution X Mass Percent

= 26.8 grams NaCl

= 670 grams X 4.00%

100%

100%

Grams of Solute = Grams of Solution X Mass Percent

= 154 grams solute

= 2,200 grams X 7.00%

100%

100%

Grams of Solute = Grams of Solution X Mass Percent

= 1,200 grams NaCl

= 6,000 grams X 20.0%

100%

Explanation:

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alex41 [277]

Answer:

The kind of ionic compound formed is MX2.

Explanation:

Element X electron  configuration is represented as [core] ns2np5. The group in the periodic table this element belong to is group 7A.  The element group is called the halogen family. Element X cannot be stated specifically, because the number is represented with n.  Element X will behave as an anions when it react with a metal(cations). Element X has a charge of -1. The element X will gain electron when it bond with a metal. Element X is a non metal . Elements  in this group are fluorine, chlorine, bromine, iodine , astatine, and tennessine . The element X have 7 valency electrons.

Element M electronic configuration is represented as  [core]ns2. The group in the periodic table this element belong to is group 2A . The element  group is called the alkaline earth metals family . Element M will behave as a cation when it bond with a non metal. Element M is a metal , therefore it will likely lose electron to form cations during bonding . The charge of element M is 2+. Element M is positively charged. Elements that belong to this group includes beryllium, magnesium, calcium, strontium, barium and radium.  Element M has 2 valency electrons.

The reaction between this 2 ions will likely form an ionic compound . The element M is the cations while the element X is the anions. The element M will lose 2 electron while 2 atoms of element  X will gain 2 electrons.Element M will lose 2 electron to attain a stable configuration while 2 atoms of element X will gain a single electron each to attain a stable configuration.

M²+ and F- . This will form MX2 when you cross multiply the charge. The kind of ionic compound formed is MX2.

6 0
3 years ago
One isotope of a metallic element has the mass number 67 and 37 neutrons in the nucleus. The cation derived from the isotope has
Anuta_ua [19.1K]
No. Of protons = mass no. - no. Of neutrons
No. Of protons = 67 - 37
= 30
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