if m&m are added to the periodic table as a "new" element what would their atomic mass be? a standard bag of m&ms = 1.75
oz and contains about 55 m&ms. (16oz = 453.6 g) put answer in (g/mol)
1 answer:
Answer: 5.43x10^23 g/mole M&M's
Explanation:
1 bag of M&M's = 1.75oz (1.75oz)*(453.6g/16oz) = 49.61 g
1 bag = 55 M&M's
(49.61 g)/55 M&M = 0.9021 g/MM
1 mole M&M's = 6.023x10^23 M&M's
(6.023x10^23 M&M's)*(0.9021 g/MM's) = 5.43x10^23 g/mole molar mass
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