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svetlana [45]
2 years ago
11

if m&m are added to the periodic table as a "new" element what would their atomic mass be? a standard bag of m&ms = 1.75

oz and contains about 55 m&ms. (16oz = 453.6 g) put answer in (g/mol)​
Chemistry
1 answer:
Allushta [10]2 years ago
4 0

Answer:  5.43x10^23 g/mole M&M's

Explanation:

1 bag of M&M's = 1.75oz       (1.75oz)*(453.6g/16oz) = 49.61 g

1 bag = 55 M&M's

(49.61 g)/55 M&M = 0.9021 g/MM

1 mole M&M's = 6.023x10^23 M&M's

(6.023x10^23 M&M's)*(0.9021 g/MM's) = 5.43x10^23 g/mole  molar mass

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Answer:

Option (2) At equilibrium, there is a much higher concentration of products than reactants.

Explanation:

The equilibrium constant for a reaction is simply the ratio of the concentration products raised to their mole ratio divided by the concentration of the reactants raised to their mole ratio.

If the equilibrium constant is close to 1 or 1, it means the concentration of the reactants and products are almost the same. But if the equilibrium constant is large as in the case of the question given above, it means that at equilibrium, the concentration of the products are higher than that of the reactants.

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A solution in which the maximum amount of solute is dissolved is said to be
ivanzaharov [21]

Saturated.

An unsaturated solution is a solution where more solute can still be added.

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H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
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Answer:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

Explanation:

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Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

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A compound is found to contain 50. 05% sulfur and 49. 95% oxygen by mass. What is the empirical formula for this compound? SO S2
jekas [21]

The empirical formula for the given compound has been \rm SO_2. Thus, option C is correct.

The empirical formula has been the whole unit ratio of the elements in the formula unit.

<h3>Computation for the Empirical formula</h3>

The given mass of Sulfur has been, 50.05 g

The given mass of oxygen has been 49.95 g.

The moles of elements in the sample has been given by:

\rm Moles=\dfrac{Mass}{Molar\;mass}

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\rm Moles\;S=\dfrac{50.05}{32}\\&#10; Moles\;S=1.56\;mol

The moles of sulfur in the unit has been 1.56 mol.

  • Moles of Oxygen:

\rm Moles\;O=\dfrac{49.95}{16} \\&#10;Moles\;O=3.12\;mol

The moles of oxygen in the unit has been 3.12 mol.

The empirical formula unit has been given as:

\rm S_{1.56}O_{3.12}=SO_2

Thus, the empirical formula for the given compound has been \rm SO_2. Thus, option C is correct.

Learn more about empirical formula, here:

brainly.com/question/11588623

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