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Alinara [238K]
3 years ago
8

11. What is the concentration (in M) of an ammonia (NH3) solution if 12.23 grams of ammonia are

Chemistry
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:  1.284M NH3

Explanation:  (12.23 grams)/(17.0 gramms/mole) = 0.7191 moles

Dissolved in 560.0 ml (=0.5600L)

(0.7191 moles)/(0.560L) = 1.284M  (4 sig figs)

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What are the 5 types of matter?
sdas [7]

The five types of states of matter are solid, liquid, gas, plasma and Bose-Einstein condensate.

Solid objects do not move a lot relative to themselves. Their molecules stay stacked neatly with no intermolecular spaces. They do not have much energy, or heat hence the molecules in solid state don't show movement.

Liquid state have more heat and more energy and a little more intermolecular space than solid. Their molecules are no longer stacked neatly due to presence of air capsules, but they still touch each other. Their structure is uncertain and can flow, their shape will alter quickly and dramatically with outside forces, but they will essentially remain a single mass unless pushed apart.

Gasses have even more energy than liquid and solid. Due to presence of high intermolecular spaces they flow like liquids, but are even more susceptible to the forces acting on them. Their molecules don’t touch each other, but are still close enough to bounce into one another frequently.

Plasma is the state of matter which is like a gas on steroids. Molecules of plasma might start in the same area, but rarely touch each other. Plasma molecules have lost electrons, and have become charged. Plasma molecules set other things on fire, and even vaporize them.

Bose-Einstein condensate or BEC was first created by scientists in the year 1995. This was created using a combination of lasers and magnets, Eric Cornell and Carl Weiman, scientists at the Joint Institute for Lab Astrophysics (JILA) in Boulder, Colorado, cooled a sample of rubidium to within a few degrees of absolute zero.

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8 0
1 year ago
Fill in the blanks to complete the table
aleksandrvk [35]

The atomic number(Z) is equal to the number of protons to equal to number of electrons.

The number of neutrons is equal to atomic mass minus the atomic number

n=A-Z

For Zn^2+, Z=28, e=28

For iron, Z=25,A=55

The number of neutrons is 55-25=30

The charge is zero

For O^2-, Z=8+2=10, n=p=10

The number of neutrons is 16-10=6

For sulfur, Z=16,A=34

For S2-, Z=16+2=18, A=34

The charge is 2-

  • The atomic number is the basis of the periodic table.
  • It is equal to the number of protons.
  • The number of neutrons is atomic mass minus atomic number.

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3 0
1 year ago
How many moles of carbon dioxide are produced from 8.73 moles of tristearin?​
matrenka [14]

Answer:

Explanation:

  8.73 mol                                         x mol

2 C57H110O6(S) + 163 O2(g)  --->  114 CO2(g) + 110 H2O(I)

2 mol                                               114 mol

8.78 mol (114mol/2 mol) =500.46 mol

8 0
3 years ago
Need help with 22 and 24<br>​
choli [55]

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

5 0
3 years ago
Read 2 more answers
Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi
AlexFokin [52]

Explanation:

The given cell reaction is as follows.

       In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : In(s) \rightarrow In^{3+}(aq) + 3e^{-} ...... (1)

At cathode; Reduction-half reaction : Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s) ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

      2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}

      3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)

Net reaction: 2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)

Thus, we can conclude that the overall cell reaction is as follows.

        2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)

4 0
3 years ago
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