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Alinara [238K]
3 years ago
8

11. What is the concentration (in M) of an ammonia (NH3) solution if 12.23 grams of ammonia are

Chemistry
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:  1.284M NH3

Explanation:  (12.23 grams)/(17.0 gramms/mole) = 0.7191 moles

Dissolved in 560.0 ml (=0.5600L)

(0.7191 moles)/(0.560L) = 1.284M  (4 sig figs)

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4 years ago
Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (
Alex

Answer:

ΔHorxn = - 11.79 KJ

Explanation:

2 SO 2 ( g ) + O 2 ( g ) ⟶ 2 SO 3 ( g )

The standard enthalpies of formation for SO 2 ( g ) and SO 3 ( g ) are Δ H ∘ f [ SO 2 ( g ) ] = − 296.8 kJ / mol Δ H ∘ f [ SO 3 ( g ) ] = − 395.7 kJ / mol

From the reaction above, 2 mol of SO2 reacts to produce 2 mol of SO3. Assuming ideal gas behaviour,

1 mol = 22.4l

x mol = 2.67l

Upon cross multiplication and solving for x;

x = 2.67 / 22.4 = 0.1192 mol

0.1192 mol of SO2 would react to produce 0.1192 mol of SO3.

Amount of heat is given as;

ΔHorxn = ∑mΔHof(products) − ∑nΔHof(reactants)

Because O2(g) is a pure element in its standard state, ΔHοf [O2(g)] = 0 kJ/mol.

ΔHorxn = 0.1192 mol * (− 395.7 kJ / mol) - 0.1192 mol * ( − 296.8 kJ / mol)

ΔHorxn = - 47.17kj + 35.38kj

ΔHorxn = - 11.79 KJ

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3 years ago
Which is an intensive property of a substance?
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Read 2 more answers
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