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Anarel [89]
2 years ago
7

What is the IUPAC name for the compound ZnO?

Chemistry
1 answer:
harina [27]2 years ago
7 0
It's 
Zn=Zinc
and  O=Oxide 
so it will be Zinc Oxide 
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The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.070% by weight. If a 21.5 g sample of this
Semmy [17]

Answer:

The molar concentration of Cu^{2+} ions in the given amount of sample is 4.73\times 10^{-5}M

Explanation:

Given that,

Mass of sample = 21.5 g

0.07 % (m/m) of copper (II) sulfate in plant fertilizer

This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present

So, in 20 g of plant fertilizer

,=\frac{0.07}{100}\times 21.5}\\=0.0151g of copper (II) sulfate is present.

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Mass of solute (copper (II) sulfate) = 0.0151 g

Molar mass of copper (II) sulfate = 159.6 g/mol

Volume of solution = 2.0 L

\text{Molarity of solution}=\frac{0.0151g}{159.6g/mol\times 2.0L}\\\\\text{Molarity of solution}=4.73\times 10^{-5}M

The chemical equation for the ionization of copper (II) sulfate follows:

CuSO_4\rightarrow Cu^{2+}+SO_4^{2-}

1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions

Molarity of copper (II) ions = 4.73\times 10^{-5}M

Hence, the molar concentration of Cu^{2+} ions in the given amount of sample is 4.73\times 10^{-5}M

4 0
3 years ago
What is the definition of bond length?
a_sh-v [17]

Answer:

C: No correct response

Explanation:

Bond length is simply defined as the distance between two atoms that are participating in a bond.

Now, looking at the options, none of the options correctly defines it this way. The closest is option E which is "distance between two electrons" but it uses the word electrons instead of atoms. Thus none of the statements are correct

6 0
2 years ago
Help please ill do anything really!!!!!!!
Volgvan

Answer:

The first one is air the second is decreases the third is water the fourth is gas and the last is liquid.

Explanation:

Hope it helps.

5 0
2 years ago
Can we all agree chemistry is hard lol
Dmitry_Shevchenko [17]

Yes, I agree.

Chemistry can be difficult.

5 0
3 years ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
galina1969 [7]

Answer:

\%\, yield\, \, SO_3=82.29

Explanation:

First write the balance eqation of chemical reaction:

2S(s) +3O_2(g) \rightarrow 2SO_3(g)

Remember writing any chemical reaction from its  elemetal form then write the elements in their natural form i.e. how that element exists in the nature here sulphur exists in solid monoatomic form in the nature and oxygen in gaseous diatomic form.

mass of oxygen given=5gram

mole of oxygen=5/32mol=0.16mol

mass of sulpher given=6gram

mole of sulpher=6/32mol=0.19mol

from the above balanced equaion;

2 mole of sulphur reacts with 3 mole Oxygen completely

1 mole of sulphur reacts with 1.5 mole Oxygen completely

0.19 mole of sulphur reacts with 1.5\times 0.19 i.e. 0.285 mole Oxygen completely.

but we have 0.16 mole so oxygen will be the limiting reagent and sulpher will be the excess reagent

so product will depend on the limiting reagent

from the balance equation

3 mole of sulpher gives 2 mole SO_3

1 mole of sulpher will give 2/3 mole SO_3

0.16 of sulpher will give 0.12 mole SO_3

mass of SO_3=9.6gram this is theoreical production of SO_3

and

actual production of SO_3 =7.9gram

\%\, yield   \,\, SO_3=\frac{Actual \,yield}{theoretical\, yield}\times 100

\%\, yield\, \, SO_3=\frac{7.9}{9.6} \times 100=82.29

\%\, yield\, \, SO_3=82.29

3 0
3 years ago
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