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3 years ago

8

If mechanical energy = kinetic energy + potential energy then as the potential energy decrease what happens to the kinetic energ

y?

1 answer:

Arisa [49]3 years ago

4 0

Explanation:

i found this hope it helps

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i want to find the volume of a block of wood it has a length of 6 inches a width of 7 inces and a height of 8 inches what is the

JulijaS [17]

Answer:

336

Explanation:

L x w x h= 6 x 7 x 8 = 336

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3 years ago

An atom has 9 electrons and 9 protons at the start . If it loses 2 electrons, the net charge on the atom will be ? If the atom i

antoniya [11.8K]

Loses 2= +2 charge
gains 4= -2 charge

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3 years ago

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The high concentration of carbon dioxide (CO2) in the atmosphere of Mars inhibits infrared radiation from escaping and keeps the

Zarrin [17]

Answer:

B

Explanation:

Mars atmosphere contains mainly carbon iv oxide, but the greenhouse effect as subdued as there is so little CO2 overall.

Venus as a planet contains 96.5% of carbon iv oxide. it doesn't contain water which can trap the CO2 as we have on earth where the oceans are able to trap the CO2 present and subdue the greenhouse effect. This inability to trap CO2 in Venus prevents infrared rays from escaping and with the fact the Venus is closer to the sun than earth and mars, its surface it extremely hot.

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3 years ago

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank

Masja [62]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is $K_c = 14.39$

Explanation:

The chemical equation for this decomposition of ammonia is

$2 NH_3$ ↔ $N_2 + 3 H_2$

The initial concentration of ammonia is mathematically represented a

$[NH_3] = \frac{n_1}{V_1} = \frac{29}{75}$

$[NH_3] = 0.387 \ M$

The initial concentration of nitrogen gas is mathematically represented a

$[N_2] = \frac{n_2}{V_2}$

$[N_2] = 0.173 \ M$

So looking at the equation

Initially (Before reaction)

$NH_3 = 0.387 \ M$

$N_2 = 0 \ M$

$H_2 = 0 \ M$

During reaction(this is gotten from the reaction equation )

$NH_3 = -2 x$ (this implies that it losses two moles of concentration )

$N_2 = + x$ (this implies that it gains 1 moles)

$H_2 = +3 x$ (this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

$NH_3 = 0.387 -2x$

$N_2 = x$

$H_2 = 3 x$

Now since

$[NH_3] = 0.387 \ M$

$x= 0.387 \ M$

$H_2 = 3 * 0.173$

$H_2 = 0.519 \ M$

$NH_3 = 0.387 -2(0.173)$

$NH_3 = 0.041 \ M$

Now the equilibrium constant is

$K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}$

substituting values

$K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}$

$K_c = 14.39$

3 0

3 years ago

When hydrogen is burned in the presence of oxygen it will form water, as per the equation: 2H2 + O2 -> 2H2O. Which types of r

nadya68 [22]

Answer:

B

Explanation:

Hydrogen is synthesized to water by adding Oxygen.

Hydrogen is oxidised to water by combustion ( burning in presence of oxygen).

4 0

3 years ago