Answer:
D. Both pull-in and hold-in windings are energized.
Explanation:
The instant the ignition switch is turned to the start position, "Both pull-in and hold-in windings are energized." This is because the moment the ignition switch is turned to the start position, voltage passes through to the S terminal of the solenoid.
The hold-in winding is attached to the case of the solenoid. Similarly, the pull-in winding is also attached to the starter motor. Thereby, the current will move across both windings by getting energized to generate a strong magnetic field.
Answer:
Digital electronics deals with the discrete-valued digital signals. In general, any electronic system based on the digital logic uses binary notation (zeros and ones) to represent the states of the variables involved in it. Thus, Boolean algebraic simplification is an integral part of the design and analysis of a digital electronic system.
Explanation:
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Answer:
the mean output power level of the channel is 100.475 mW
Explanation:
Given the data in the question;
for the first section; attenuation
16 = 10log₁₀ 400/P₂
P₂ = 10.0475 mW
For the second section; amplification
20 = 10log₁₀ p₂/10.0475
p₂ = 1004.75 mW
For the third section; attenuation
10 = 10log₁₀ p₂/1004.75
p₂ = 100.475 mW
i.e the mean output power level is 100.475 mW
or better still overall attenuation channel = ( 16 - 20) + 10 = 6dB
so
6 = 10log₁₀ 400/P₂
p₂ = 100.475 mV
the mean output power level of the channel is 100.475 mW
Answer:
The highest grade level is college.
