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kipiarov [429]
2 years ago
13

A cylindrical container is 150mm in diameter and weights 2.25n when empty

Engineering
1 answer:
stellarik [79]2 years ago
3 0

Answer:

.

Explanation:

.

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technician a uses a current output test to check ac generator output. technician b uses a voltage output test to check output. w
expeople1 [14]

Answer:

both

Explanation:

Both the technician are correct, ac generator output can be tested in both ways. The two ways are  current output test to check ac generator output. and  voltage output test to check output.

7 0
3 years ago
Explain why it is not advisable to wear Ornament like ring at work shop​
disa [49]

The reason that it is not advisable to wear Ornament like ring at work shop​ is that rings can be easily get caught and fingers or the hands of the person can be injured, cut, scared etc.

<h3>Why should you not wear a ring at work?</h3>

Jewelry is known to bring about a lot of safety hazards for people working around chemicals and others.

Note that the reason that it is not advisable to wear Ornament like ring at work shop​ is that rings can be easily get caught and fingers or the hands of the person can be injured, cut, scared etc.

Learn more about Ornament from

brainly.com/question/24286720

#SPJ1

8 0
2 years ago
Astronauts who landed on the moon during the Apollo 15, 16, and 17 missions brought back a large collection of rocks to the eart
stiks02 [169]

Answer: a) W(earth) = 935.62 lbs

b) Mass of rocks in slugs = 29.06 slugs

Explanation:

a) From Newton's law, W = mg. Whether on the moon or on earth. Although, the mass of the rocks everywhere is the same, that is, mass of rocks on the moon = mass of rocks on earth.

W(moon) = mg(moon)

W(moon) = 154 lbs

g(moon) = 5.30 ft/s2

m = W(moon)/g(moon) = 154/5.3 = 29.06 lb.s2/ft

W(earth) = m g(earth)

g(earth) = 32.2 ft/s2

W(earth) = 29.06 × 32.2 = 935.62 lbs.

b) A slug = 1 lb.s2/ft, therefore the mass of the rocks in slugs is 29.06 slugs.

QED!

8 0
3 years ago
The interior wall of a building is made from 2×4 wood studs, plastered on one side. If the wall is 13 ft high, determine the loa
Elanso [62]

Answer:

load  = 156 lb/ft

Explanation:

given data

interior wall of a building = 2×4 wood studs

plastered = 1 side

wall height =  13 ft

solution

we get here load so first we get wood stud load  and that is  

we know here from ASCE-7 norm

dead load of 2 x 4 wood studs with 1 side plaster  = 12 psf

and we have given height 13 ft

so load will be =  12 psf × 13 ft

load  = 156 lb/ft

7 0
3 years ago
A section of highway has a free-flow speed of 55 mph and a capacity of 3300 veh/hr. In a given hour, 2100 vehicles were counted
alexira [117]

Answer:

Space mean speed = 44 mi/h

Explanation:

Using Greenshield's linear model

q = Uf ( D - D^{2}/Dj )

qcap = capacity flow that gives Dcap

Dcap = Dj/2

qcap = Uf. Dj/4

Where

U = space mean speed

Uf =  free flow speed

D = density

Dj = jam density

now,

Dj = 4 × 3300/55

    = 240v/h

q = Dj ( U - U^{2}/Uf)

2100 = 240 ( U - U^{2}/55)

Solve for U

U = 44m/h

5 0
3 years ago
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