A cylindrical container is 150mm in diameter and weights 2.25n when empty

Air flows at 45m/s through a right angle pipe bend with a constant diameter of 2cm. What is the overall force required to keep t

HACTEHA [7]

Answer:

b)1.08 N

Explanation:

Given that

velocity of air V= 45 m/s

Diameter of pipe = 2 cm

Force exerted by fluid F

$F=\rho AV^2$

So force exerted in x-direction

$F_x=\rho AV^2$

$F_x=1.2\times \dfrac{\pi}{4}\times 0.02^2\times 45^2$

F=0.763 N

So force exerted in y-direction

$F_y=\rho AV^2$

$F_y=1.2\times \dfrac{\pi}{4}\times 0.02^2\times 45^2$

F=0.763 N

So the resultant force R

$R=\sqrt{F_x^2+F_y^2}$

$R=\sqrt{0.763^2+0.763^2}$

R=1.079

So the force required to hold the pipe is 1.08 N.

3 0

3 years ago

Is EPA is the organization that was formed to ensure safe and health working conditions for workers by setting and enforcing sta

mr_godi [17]

Let me search this up

3 0

2 years ago

2. Write a Java program that generates a new string by concatenating the reversed substrings of even indexes and odd indexes sep

Nana76 [90]

Answer:

public class Main {
public static void main(String[] args) {
String testString = "abscacd";
String evenStr = "";
String oddStr = "";
for(int i=testString.length() - 1; i >= 0; i--){
if(i % 2 == 0){
evenStr += testString.charAt(i);
}
else{
oddStr += testString.charAt(i);
}
}
System.out.println(evenStr + oddStr);
}
}

Explanation:

Firstly, let declare a variable testString to hold an input string "abscacd" (Line 1).

Next create another two String variable, evenStr and oddStr and initialize them with empty string (Line 5-6). These two variables will be used to hold the string at even index and odd index, respectively.

Next, we create a for loop that traverse the characters of the input string from the back by setting initial position index i to testString.length() - 1 (Line 8). Within the for-loop, create if and else block to check if the current index, i is divisible by 2, (i % 2 == 0), use the current i to get the character of the testString and join it with evenStr. Otherwise, join it with oddStr (Line 10 -14).

At last, we print the concatenated evenStr and oddStr (Line 18).

4 0

2 years ago

When would working with machinery be a common type of caught-in and caught-between<br> hazard?

tigry1 [53]

Answer:

A working with machinery be a common type of caught-in and caught-between hazard is described below in complete detail.

Explanation:

“Caught in-between” accidents kill mechanics in a variety of techniques. These incorporate cave-ins and other hazards of tunneling activity; body parts extracted into unconscious machinery; reaching within the swing range of cranes and other installation material; caught between machine & fixed objects.

6 0

3 years ago

Can someone answer plz!! It’s 24 points

fgiga [73]

Explanation:

750 microvolt is your answer

please mark as brilliant

3 0

3 years ago

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