Answer:
Check the explanation
Explanation:
Assumptions.
1. The surfaces are diffuse, may and opaque
2. steady operating conditions exist
3. Heat transfer from and to the surfaces is only due to Radiation
Consider the base surface to be surface 2 the top surface to be surface and the side surfaces to surface 3 1. cubical furnace can be considered to be three-surface enclosure. the areas and black body emissive powers of surfaces can be calculated as seen in the attached images below.
Answer:
View Image
Explanation:
You didn't provide me a picture of the opamp.
I'm gonna assume that this is an ideal opamp, therefore the input impedance can be assumed to be ∞ . This basically implies that...
- no current will go in the inverting(-) and noninverting(+) side of the opamp
- V₊ = V₋ , so whatever voltage is at the noninverting side will also be the voltage at the inverting side
Since no current is going into the + and - side of the opamp, then
i₁ = i₂
Since V₊ is connected to ground (0V) then V₋ must also be 0V.
V₊ = V₋ = 0
Use whatever method you want to solve for v_out and v_in then divide them. There's so many different ways of solving this circuit.
You didn't give me what the input voltage was so I can't give you the entire answer. I'll just give you the equations needed to plug in your values to get your answers.
Answer:
<em>v</em><em> </em>= T/(2R)
Explanation:
Given
R = radius
T = strength
From Biot - Savart Law
d<em>v</em> = (T/4π)* (d<em>l</em> x <em>r</em>)/r³
Velocity induced at center
<em>v </em>= ∫ (T/4π)* (d<em>l</em> x <em>r</em>)/r³
⇒ <em>v </em>= ∫ (T/4π)* (d<em>l</em> x <em>R</em>)/R³ (<em>k</em>) <em>k</em><em>:</em> unit vector perpendicular to plane of loop
⇒ <em>v </em>= (T/4π)(1/R²) ∫ dl
If l ∈ (0, 2πR)
⇒ <em>v </em>= (T/4π)(1/R²)(2πR) (<em>k</em>) ⇒ <em>v </em>= T/(2R) (<em>k</em>)
Answer:
Please, see the attachment.
Explanation:
First, we have to create two input boxes that allows the user to write the current year in one of them and his/her birth year in the another one. Also, we have to create a label that will show the result of the desired variable. We can write a message "Your age is:" and it will be attached to the result.
For the algorithm, let's call the variables as follows:
CY = Current Year
BY = Birth Year
X = Age of user
When the user inserts the current year and his/her birth year, the program will do the following operation:
X = CY - BY; this operation will give us the age of the user
After this the user will see something like "Your age is:" X.