Answer:
volumetric flow rate = 
Velocity in pipe section 1 = 
velocity in pipe section 2 = 12.79 m/s
Explanation:
We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.
The density of water is = 997 kg/m³
density = mass/ volume
since we are given the mass, therefore, the volume will be mass/density
25/997 = 
volumetric flow rate = 
Average velocity calculations:
<em>Pipe section A:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

<em>Pipe section B:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

Do you have a picture of the question?
JT2 oaoaosnforeneomdocdmsnsksmsmsodnfnfj
Answer:
B. G = 333 mS, B = j250 mS
Explanation:
impedance of a circuit element is Z = (3 + j4) Ω
The general equation for impedance
Z = (R + jX) Ω
where
R = resistance in ohm
X = reactance
R = 3Ω X = 4Ω
Conductance = 1/R while Susceptance = 1/X
Conductance = 1/3 = 0.333S
= 333 mS
Susceptance = 1/4 = 0.25S
= 250mS
The right option is B. G = 333 mS, B = j250 mS