The answer & explanation for this question is given in the attachment below.
umm , is it okay if we do this on microsoft word , cuz i cant send pics of answers here...
Answer:
-50.005 KJ
Explanation:
Mass flow rate = 0.147 KJ per kg
mass= 10 kg
Δh= 50 m
Δv= 15 m/s
W= 10×0.147= 1.47 KJ
Δu= -5 kJ/kg
ΔKE + ΔPE+ ΔU= Q-W
0.5×m×(30^2- 15^2)+ mgΔh+mΔu= Q-W
Q= W+ 0.5×m×(30^2- 15^2) +mgΔh+mΔu
= 1.47 +0.5×1/100×(30^2- 15^2)-9.7×50/1000-50
= 1.47 +3.375-4.8450-50
Q=-50.005 KJ
Answer:
a) V(t) = Ldi(t)/dt
b) If current is constant, V = 0
Explanation:
a) The voltage, V(t), across an inductor is proportional to the rate of change of the current flowing across it with time.
If V represents the Voltage across the inductor
and i(t) represents the current across the inductor in time, t.
V(t) ∝ di(t)/dt
Introducing a proportionality constant,L, which is the inductance of the inductor
The general equation describing the voltage across the inductor of inductance, L, as a function of time when a current flows through it is shown below.
V(t) = Ldi(t)/dt ..................................................(1)
b) If the current flowing through the inductor is constant i.e. does not vary with time
di(t)/dt = 0 and hence the general equation (1) above becomes
V(t) = 0
