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QveST [7]
2 years ago
11

1Which statement correctly applies to a car that changes its velocity over a period of time?

Physics
2 answers:
slavikrds [6]2 years ago
5 0

Answer:b a nonzero net force is acting on it

Explanation:

ahrayia [7]2 years ago
5 0

1) D; Forces are acting on it.

2) A; Graphs visually show the relationship between the variables under investigation.

  • 1) Velocity is same as speed just that it has direction. Now Newton's first law of motion which is called law of inertia states that an object will continue in its present state of rest rest or remain in constant motion unless an external force acts on it.

This means that for a cars speed to change, according to this law, it means external forces have acted on it.

Thus, option D is correct.

D; Forces are acting on it.

  • 2) We want to show the relationship between force and acceleration using either table or graph.

Now, a table will just use rows and columns to show us the value of a force per given acceleration. It doesn't show us a trend in terms of line or curve like the way graph will show.

This means that graphs give a better visual representation of the relationship between two variables than tables will do.

Thus, option A is correct.

Read more at;

brainly.com/question/11724238

brainly.com/question/24448005

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If Star A is magnitude 1.0 and Star B is magnitude 9.6 , which is brighter and by what factor?
ludmilkaskok [199]

Answer:

Star A is brighter than Star B by a factor of 2754.22

Explanation:

Lets assume,

the magnitude of star A = m₁ = 1

the magnitude of star B = m₂ = 9.6

the apparent brightness of star A and star B are b₁ and b₂ respectively

Then, relation between the difference of magnitudes and apparent brightness of two stars are related as give below: (m_{2} - m_{1}) = 2.5\log_{10}(b_{1}/b_{2})

The current magnitude scale followed was formalized by Sir Norman Pogson in 1856. On this scale a magnitude 1 star is 2.512 times brighter than magnitude 2 star. A magnitude 2 star is 2.512 time brighter than a magnitude 3 star. That means a magnitude 1 star is (2.512x2.512) brighter than magnitude 3 bright star.

We need to find the factor by which star A is brighter than star B. Using the equation given above,

(9.6 - 1) = 2.5\log_{10}(b_{1}/b_{2})

\frac{8.6}{2.5}  = \log_{10}(b_{1}/b_{2})

\log_{10}(b_{1}/b_{2}) = 3.44

Thus,

(b_{1}/b_{2}) = 2754.22

It means star A is 2754.22 time brighter than Star B.

3 0
3 years ago
US
erastovalidia [21]

Answer:11.5m

Explanation:

6 0
2 years ago
Rahul has 2 bulbs connected across two cells in a simple circuits shown. How can he make the bulbs glow dimmer?
Ray Of Light [21]

Answer:

in the parallel connection the light bulbs shine less than in the series connection

Explanation:

In a series circuit the current through the whole circuit is the same, therefore the power (brightness) of each bulb is

           P = i² R

where R is the resistance of each bulb and i the current of the circuit.

If we connect the light bulbs and the cells in parallel, the current in the circuit is the sum of the east that passes through each light bulb,

            i = i₁ + i₂

if the two light bulbs are the same

           i = 2 i₁

           i₁ = i / 2

so the power of each bulb is is

           P = i₁² R

           P = R i² / 4

           P = ¼ P_initial

Therefore we see that in the parallel connection the light bulbs shine less than in the series connection

3 0
3 years ago
Please help will mark brainliest
andreyandreev [35.5K]

Answer:

b

Explanation:

it melts yes but it's still water [same element] so there fore it's a physical change

7 0
3 years ago
Read 2 more answers
When a mass of 29 g is attached to a certain spring, it makes 20 complete vibrations in 3.1 s. What is the spring constant of th
never [62]

Answer:

The spring constant of the spring is 47.62 N/m

Explanation:

Given that,

Mass that is attached with the spring, m = 29 g = 0.029 kg

The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,

f=\dfrac{20}{3.1}

f = 6.45 Hz

The frequency of oscillator is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

k is the spring constant

k=4\pi^2f^2m

k=4\pi^2\times (6.45)^2\times 0.029

k = 47.62 N/m

So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.

4 0
3 years ago
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