Answer: 337J/kg
Explanation:
(a) For air, take k = 1.40, R = 287 J/kg ⋅ K, and cp = 1005 J/kg ⋅K. The adiabatic steady-flow energy equation (9.23) is used to compute the downstream velocity:+ = = + = +2 2 2p 21 1 1c T V constant 1005( 260) (75) 1005(207) V or .2 2 2
Ans2mV 335 s≈2 1 p 2 1 2 1 207 273 30Meanwhile, s s c ln(T /T ) R ln( p /p ) 1005 ln 287 ln ,260 273 140+ − = − = − ÷ ÷ +or s 2 − s1 = −105 + 442 ≈ 337 J/kg ⋅ K Ans.(a)
(b) For argon, take k = 1.67, R = 208 J/kg ⋅ K, and cp = 518 J/kg ⋅ K. Repeat part (a):2 2 2p 21 1 1c T V 518(260) (75) 518(207) V , solve .2 2 2 Ans+ = + = + 2mV 246 1 207 273 30s s 518 l n 208 ln 54 320 . (b)260 273 140
Answer: a)True
Explanation: Takt time is defined as the average time difference between the production of the two consecutive unit of goods by the manufacturer and this rate is matched with the demand of the customer. This is the time which is calculated to find the acceptable time for which the goods unit must be produced by the factory to meet the needs of the customer. Therefore , the statement is true that takt time is the rate at which a factory must produce to satisfy the customer's demand.
Answer:
(a) %RH = 45%
(b) Dp Temp = 58 °F (14.44 °C)
Explanation:
We can obtain the results easily and faster with a psychometric chart. (See the attachment). In the graph we can see how we obtain results crossing the respective data (marked in red).
First, for the relative humidity, we cross the humidity ratio (starting from the right side) with the dry temperature (horizontal axis). In that way we can read from the relative humidity curves the value of 45%.
After that, we extend the horizontal line from the right side until the left side and cross it with the 100% saturation curve in order to read the dew point temperature. Here we obtain the value 58 °F (14.44 °C)
Answer:transmission
Explanation:
i’m not entirely familiar with this but i’m sure it’s transmission!