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3 years ago

Should aircraft wings have infinite stiffness?

2 answers:

5 0

Answer: 2.1.3 The evolution of aircraft wing structures-form follows function Torsional stiffness is fundamental to all aeroelastic approaches unity, 0 will..

HOPE IT HELPS GIVE ME BRAINLIST PLEASE :)

Colt1911 [192]3 years ago

3 0

Answer:

No, they need to be somewhat flexible so that forces such as turbulance don't shear the wing off.

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Find the remaining trigonometric function of 0 if

amm1812

Answer:

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3 years ago

In Ohio a registered vehicle must have a valid license plate displayed on the vehicle within;

sineoko [7]

You can't legally drive it on the road without proper plates. If you will be transferring plates from a vehicle currently registered to you, you have 30 days to register the plates to the new car.

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3 years ago

Read 2 more answers

The in situ moisture content of a soil is 18% and the moist (total) unit weight is 105 pcf. The soil is to be excavated and tran

densk [106]

Answer: Volume= 1.16 yd³

Explanation:

We are given the in-situ moisture content= 18% and moist unit weight= 105 pcf

First we find out the dry unit weight

Dry unit weight= Moist unit weight / (1+ moisture content)

Dry unit weight= $\frac{105}{1.18}$

Dry unit weight= 88.983 pcf

Now, to find the volume ( in terms of each cubic yard i.e 1 yd³ we have

Volume = Dry unit weight compacted / Dry unit weight (in-situ) * 1 yd³

Volume= $\frac{103.5}{88.983} * 1$

Volume= 1.16 yd³

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4 years ago

If an object is near the surface of the earth the variation of its weight with distance from the center of the earth can ofteb b

zalisa [80]

Answer:

h=32.1 km

Explanation:

<em>solution:</em>

using newton law of gravitational attraction and newton second law:

$W=\frac{Gmm_{E} }{r^{2} } \\a=\frac{Gm_{E}}{r^{2}} \\W=ma\\$

$m_{E}= mass of earth$

r= distance between two masses

at sea level

a=g

$r=R_{E}$

$a=\frac{Gm_{E}}{r^{2}}$ .............................(1)

$Gm_{E} =gR_{E}^2$ .........................(2)

by substituting (2) and (1) $a=g\frac{R_{E}^2 }{r^{2} }$ acceleration due to gravity at a distance r from the centre of the earth in terms of g (sea level)

so the weight of the object at a distance r from the centre of the earth (W=ma)

W=mg(Re^2/r^2)..........(3)

h the height above the surface of the earth: r=Re+h

putting the value of r in eq (3)

W=mg(Re/Re+h)^2

W=0.99 mg

solving for height h:

h=Re(1/√0.99)-(1))

h=32.1 km

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3 years ago

How much does it cost to repair a broken train? (Fill in the blanks)

Lana71 [14]

900,000 dollors muny

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2 years ago