Answer:
8.62m/s²
Explanation:
the particle is experiencing both translational and circular motion
v=4t²
==8t
at t=1s, =8(1)=8m/s²
=
at t=1, v= 4(1)² = 4m/s
=4²/5
=3.2m/s²
∴ magnitude of total acceleration, a
a=
a=
a=
a=
a=8.62m/s²
Answer:
False
Explanation:
Bella counts products in finished goods inventory and she counts kits in various stages of manufacturing.
Answer:
The escape systems not working