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Natalija [7]
3 years ago
12

PLEASE HELP ME ASAP!!! 10 POINTS!!

Chemistry
1 answer:
lapo4ka [179]3 years ago
4 0

Explanation:

A) fission: Iodine-140 (atomic number = 53)

B) fusion: 1 neutron

C) fission: Uranium-233 (atomic number = 92)

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Solve using significant figures <br> 8.647 + 45.969
Murrr4er [49]

Answer:

54.616

Explanation:

8.647 + 45.969

or rewrite for easier look:

45.969 +

 8.647 =

54.616

Hope this helped :3

 

5 0
3 years ago
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Identify one natural process that may cause sudden climate changes.
Vesnalui [34]

Answer:

Global Warming , Volcanic Eruption

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3 years ago
What is the pH of a 8.7 x 10^-12 M OH- solution ? pH= ?
vivado [14]
PH=14-pOH

pOH=-lg[OH⁻]

pH=14+lg[OH⁻]

pH=14+lg(8.7*10⁻¹²)=14-11.06=2,94
5 0
3 years ago
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How many moles of water are produced when 3.0 moles of hydrogen gas react with 1.8 moles of oxygen gas?
swat32

Sorry for the late response but for this question, the answer is 3 moles of water.

8 0
3 years ago
Find the formula for the hydrate<br>0.737 g MgSO3 and 0.763 g H2O
babunello [35]

The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

To know more about hydrate compound, visit the below link:

brainly.com/question/22411417

#SPJ1

6 0
2 years ago
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