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Find compound interest on12600rupees for 2years at10% per annum compounded anually<br>

vekshin1

Answer:

₹2520

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 10%/100 = 0.1 per year,

then, solving our equation

I = 12600 × 0.1 × 2 = 2520

I = ₹ 2,520.00

The simple interest accumulated

on a principal of ₹ 12,600.00

at a rate of 10% per year

for 2 years is ₹ 2,520.00.

3 0

2 years ago

5xy + 4yz + 3zx for x = -1, y =-3, z = 4

neonofarm [45]

Answer:

-45

Step-by-step explanation:

5 *-1 *-3= 15

4 *-3 *4= -48

3 *4 *-1=-12

15 -48 -12= -45

8 0

2 years ago

A woodworker makes wooden checkerboards. her profit is a function of the price she charges. this graph shows her total profits,

pantera1 [17]

Answer:

Option B.

Step-by-step explanation:

Remember that the profit is defined as the difference between the revenue and the cost.

So, having a profit y = 0 means that the woodworker did not win nor lose anything.

Then the zeros of the function, the values of x such that the graph intersects the x-axis, are the prices such that she does not win nor loss anything.

In the graph we can see that the zeros are at:

x = 15 (the first one)

x = 70 (the second one)

so the zeros are at x = 15 and x = 70, and these are the prices such that the profit is zero, so at these prices she does not make nor lose money.

The correct option is B.

8 0

2 years ago

-17+ 1/4 x + 1/4 x + 31 = 24

wlad13 [49]

<h2><u>Answer:</u></h2><h2><u></u> $\boxed{x=20}$ <u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Combine like terms:</h3>

$\frac{1}{4}x+\frac{1}{4}x=\frac{1}{2}x$

<em> - We do this because we need 1 Number/Variable left over. </em>

<u>Equation at the end of Step 1:</u>

<u /> $-17+\frac{1}{2}x+31=24$ <u />

<em />

$-17+31=14$

<em> - We do this because we can only have 1 number on each side of the equals. (This doesn't count towards the number connected to the variable.)</em>

<u>Equation at the end of Step 2:</u>