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3 years ago

♔♔Why is mass conserved in chemical reactions?❦❦❦

Chemistry

2 answers:

Slav-nsk [51]3 years ago

7 0

Answer:

Heya..

here's ur answer ⤵️

Explanation:

Mass is never lost or gained in chemical reaction.

we say that mass is always conserved. In other words the total mass of products at the end of the reaction is equal to the total mass of the Reactants at the beginning. This is because no atom are created or destroyed during chemical reactions.

Hope this helps u 

Allushta [10]3 years ago

5 0

Answer:

Atoms are not created or destroyed by chemical reactions. Also, matter is neither created nor destroyed, it just changes form. Matter cannot be created or destroyed. ... The Law of Conservation of Mass states that in a chemical reaction the total mass of reactants is equal to the total mass of products.

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

For example, when wood burns, the mass of the soot, ashes, and gases equals the original mass of the charcoal and the oxygen when it first reacted. So the mass of the product equals the mass of the reactant.

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Annie learns that the compound sulfuric acid is called the universal chemical. The acid is used in everything from gasoline to p

pochemuha

Answer:

D. H2SO4

Explanation:

The chemical formula of a compound is an expression that stares out the elements (in form of symbols)present in a compound and the number of the atoms.

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There is one sulphur (S) atom, 4 oxygen(O) atoms and 2 hydrogen (H) atoms

The chemical formula is;

H2SO4.

The correct option is option D.

4 0

3 years ago

How many grams of water are produced if 3.2 moles of hydrogen reacts

kotykmax [81]

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3 years ago

Calculate the pH of the following simple solutions:

IceJOKER [234]

Answer :

(1) pH = 1.27

(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

(1) 53.1 mM HCl

Concentration of HCl = $53.1mM=53.1\times 10^{-3}M$

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= $53.1\times 10^{-3}M$

pH : It is defined as the negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pH=-\log (53.1\times 10^{-3})$

$pH=1.27$

(2) 0.223 M KOH

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (0.223)$

$pOH=0.65$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35$

(3) 53.1 mM HCl + 0.223 M KOH

Buffer : It is defined as a solution that maintain the pH of the solution by adding the small amount of acid or a base.

It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

5 0

3 years ago

This is the balances equations. C3H8 + 5O2 → 3CO2 + 4H2O How many moles of oxygen are required to produce 37.15 g CO2

AleksandrR [38]

Molar mass O2 = 31.99 g/mol

Molar mass CO2 = 44.01 g/mol

Moles ratio:

C3H8 + 5 O2 = 3 CO2 + 4 H2O

5 x 44.01 g O2 ---------------- 3 x 44.01 g CO2
( mass of O2) ------------------ 37.15 g CO2

mass of O2 = 37.15 x 5 x 44.01/ 3 x 44.01

mass of O2 = 8174.8575 / 132.03

mass of O2 = 61.916 g

Therefore:

1 mole O2 ----------------- 31.99 g
moles O2 -------------------- 61.916

moles O2 = 61.916 x 1 / 31.99

moles = 61.916 / 31.99 => 1.935 moles of O2

4 0

3 years ago

Given the balanced equation representing a reaction:

sleet_krkn [62]

4Al(s) + 3O2(g) --> 2Al2O3(s) This is the balanced.
From the equation:

4 moles of Al required 3 moles of O2 to produce 2 moles of Al2O3

3 moles of O2 reacted with 4 moles of Al to produce 2 moles of Al2O3
1 mole of O2 reacted with 4/3 moles of Al to produce 2/3 moles of Al2O3 (Divide by 3)
4.5 moles of O2 reacted with (4/3 *4.5) moles of Al to produce (2/3*4.5) moles of Al2O3

4.5 moles of O2 reacted with 6moles of Al to produce 3moles of Al2O3

(3) is the answer. 6 mol of Al.

7 0

3 years ago

♔♔Why is mass conserved in chemical reactions?❦❦❦​

♔♔Why is mass conserved in chemical reactions?❦❦❦