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Maru [420]
2 years ago
6

1. What are the two factors affecting friction

Physics
1 answer:
bija089 [108]2 years ago
5 0
Answer: a.) Roughness of the surfaces in contact with each other .
Higher the roughness of surfaces in contact with each other, greater is the friction between bodies. Force of friction will be less between smooth surfaces.

b.) Weight of the sliding/rolling body: greater the weight of the moving body on the surface, more is the force of friction on the body by the surface.

I hope this helps

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A roller coaster is hard to stop because it has a lot of inertia. Infer using newtons first law
olchik [2.2K]
Lol i think i had the same worksheet!! lol anyway look up newtons first law and it will be pretty self explanatory from there
4 0
4 years ago
Lymph ducts are more similar to arteries than veins.<br> A. <br> True<br> B. <br> False
Strike441 [17]

Answer:

False

Explanation:

5 0
4 years ago
8. two +1 C charges are separated by 3000m. What is the magnitude of the electric force between them?
Sidana [21]

Answer:

1000 N

Explanation:

The magnitude of the electrostatic force between two charged object is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb constant

q1, q2 is the magnitude of the two charges

r is the distance between the two objects

Moreover, the force is:

- Attractive if the two forces have opposite sign

- Repulsive if the two forces have same sign

In this problem:

q_1=q_2=+1C are the two charges

r = 3000 m is their separation

Therefore, the electric force between the charges is:

F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N

8 0
3 years ago
Light travels at a speed of 3.00 x 10^11 cm/s. What is the speed of light in kilometers/hour?
rewona [7]

As 1 km = 1000 m = 1000,00 cm,

So, 1 cm = (1/1000,00) km

1 hour = 60 × 60 s = 3600 s

So,  1 s = (1 / 3600) hour

The light travels at a speed of 3.00 \times 10^{11}  \ cm/s.

In kilometer/hour,

3.00 \times 10^{11}  \ cm/s = 3.00 \times 10^{11} \frac{(1/1000,00) km}{ (1 / 3600) hour} = 108 \times 10^8 \ km/hour


4 0
4 years ago
How can you increase the torque you are putting on a lever, without exerting any more force?
Mariana [72]

Answer:

See below

Explanation:

Torgue = f * distance    basically ...so if you want to increase torque with same  f   then the distance ( lever arm)  must be increased

4 0
3 years ago
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