Answer:
2) f = 0.707 Hz
Explanation:
Given m₁ = 1.0 kg , f₁ = 1.0 Hz
So using the equation
f₁ = ( 1 / 2 π ) * √K / m₁
Solve to determine K' constant of spring
K = m * ( 4 π ² * f ² )
K = 1.0 kg * ( 4 π ² 1.0² Hz )
K = 39.4784176
So given 2.0 kg the frequency can be find using formula
f₂ = ( 1 / 2 π ) * √K / m₂
f₂ = ( 1 / 2 π ) * √39.4784176 / 2.0 kg
f₂ = 0.707 Hz
Many of today’s mathematicians use computers to test cases that are either too time-consuming or involve too many variables to test manually, allowing the exploration of theoretical issues that were impossible to test a generation ago.
Answer: Option A
<u>Explanation:</u>
One of the most useful inventions in scientific world are the computers. We can use different programming language and create programs in them. These programs help other to solve difficult problems. Most of the theoretical problems in science can be solved by using these programming features in computer within a specific time limit.
Otherwise, earlier mathematician used to take months to solve a complex mathematical problem manually, but now with the inclusion of computers, the mathematician can solve the problems containing more number of variables or other theoretical issues.
<span>False. Water is the best and the only hydrating property that should be consumed prior to any exercise. Gatorade is good to take while doing exercise or after to give you a boost of energy but should never be consumed excessively. These drinks can increase your heart rate and in my opinion are no substitute for water.</span>
One point will be X1,Y1 and the other will be X2,Y2. It does not matter which is which except that X1 and Y1 have to be the same point and X2 and Y2 have to be the same point. For example, let's say you were given (2,3) and (6,8). No matter which point is X1,Y1 and the other is X2,Y2, the slope will still be 5/4.
The rise is the change in y from one point to the other. The run would be the change in x from one point to the other.
Answer:
Explanation:
the sphere is solid and conducting, so the charge is uniformly distributed over its volume.
