All categories

3 years ago

What Doppler shift would an astronomer notice for the spectral light from a galaxy moving away from Earth? Choose

Physics

1 answer:

Misha Larkins [42]3 years ago

4 0

Answer:

In contrast, the light from a star moving away from us seems to shift towards longer wavelengths. As this is towards the red end of the spectrum, astronomers call it redshift

Explanation:

You might be interested in

The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?

ch4aika [34]

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E + P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

7 0

3 years ago

Suppose that a sound has initial intensity β1 measured in decibels. This sound now increases in intensity by a factor f. What is

topjm [15]

Answer:

β2= β1+10*f

Explanation:

comparing β2 and β1, it is said that β2 is increased by a factor of f.

for each factor of f, there is a 10*f dB increase.

therefore if the β1 is increases by an intensity of factor f

the new intensity would be β1+ 10*f

4 0

3 years ago

On a roller coaster, riders can experience a force of up to 4 g. What is the maximum acceleration of the roller coaster?

yKpoI14uk [10]

m/s^2 is 39.2266

is the answer If thats what you needed

7 0

3 years ago

Read this /https://www.carbonbrief.org/polar-bears-and-climate-change-what-does-the-science-say

DerKrebs [107]

Melting ice would damage this polar bears habitat meaning the polar bear may decrease

5 0

3 years ago

LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.

Svetradugi [14.3K]

Answer:

i) E = 269 [MJ] ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

$E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.$

$W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]$

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

$E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]$

8 0

3 years ago