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stealth61 [152]
3 years ago
6

What conclusions can you draw about the relationship between the temperature of a ball and its bounce height? Is there a direct

or inverse relationship? Write an evidence-based claim.
Physics
1 answer:
just olya [345]3 years ago
6 0

<u><em>The temperature of the ball is directly proportional to its bounce height.</em></u>

This is dealing about the effect of temperature on a bouncing ball.

  • According to Gay-Lussacs Law, Pressure is directly proportional to temperature when the volume is constant. This means that an increase in temperature will lead to an increase in pressure.

  • Now, Pressure is Force/Area and so the higher the air pressure, the higher will be the force on the ball and consequently, the higher the ball will bounce. Likewise, the lower the temperature, the lower the pressure and thus the lower the height at which the ball will bounce.

  • This means, we can conclude that since temperature is directly proportional to pressure and pressure is directly proportional to the height of bounce of the ball, the temperature of the ball is directly proportional to its bounce height.

Read more at; brainly.com/question/24555654

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If the velocity of a car is 45 km/h west how far can it travel in 0.5 hours?
marissa [1.9K]

Answer: 22.5 km

Explanation: Solution:

v=d/t

Derive to find d

d= vt

= 45 km/h x 0.5 h

= 22.5 km

Cancel hours and the remaining unit is in km.

6 0
3 years ago
When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Bezzdna [24]

Answer:

Distance between the charges, r = 0.8 meters

Explanation:

Given that,

Charge 1, q_1=+8.4\ \mu C=+8.4\times 10^{-6}\ C

Charge 2, q_2=+5.6\ \mu C=+5.6\times 10^{-6}\ C

Repulsive force between charges, F = 0.66 N

Let r is the distance between charges. The formula for the electrostatic force is given by :

F=k\dfrac{q_1q_2}{r^2}

r=\sqrt{\dfrac{kq_1q_2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times 8.4\times 10^{-6}\times 5.6\times 10^{-6}}{0.66}}

r = 0.8009 meters

or

r = 0.8 meters

So, the distance between the charges i 0.8 meters. Hence, this is the required solution.

4 0
3 years ago
What is the relationship between mass and inertia? Give an example
ad-work [718]

Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it ha

5 0
3 years ago
1) Halving the distance (i.s., decreasing by a factor of two) between two charged objects will cause the electrical force betwee
Vedmedyk [2.9K]

Answer:

Explanation:

For an electric force, F the formula:

F = kQq/r^2

Given:

r2 = 1/2 × r1

F1 × r1 = k

F1 × r1 = F2 × r2

F2 = (F1 × r1^2)/(0.5 × r1)^2

= (F1 × r1^2)/0.25r1^2

= 4 × F1.

7 0
4 years ago
An electric motor rotating a workshop grinding wheel at 1.00 × 10² rev/min is switched off. Assume the wheel has a constant nega
ololo11 [35]

An electric engine turning a workshop sanding rotation at 1.00 × 10² rev/min is switched off. Take the wheel includes a regular negative angular acceleration of volume 2.00 rad/s². 5.25 moments long it takes the grinding rotation to control.

<h3>What is negative angular acceleration?</h3>
  • A particle that has a negative angular velocity rotates counterclockwise.
  • Negative angular acceleration () is a "push" that is hence counterclockwise.
  • The body will speed up or slow down depending on whether and have the same sign (and eventually go in reverse).
  • For instance, when an object rotating counterclockwise slows down, acceleration would be negative.
  • If a rotating body's angular speed is seen to grow in a clockwise direction and decrease in a counterclockwise direction, it is given a negative sign.
  • It is known that a change in the linear acceleration correlates to a change in the linear velocity.

Let t be the time taken to stop.

ω = 0 rad/s

Use the first equation of motion for rotational motion

ω = ωo + α t

0 = 10.5 - 2 x t

t = 5.25 second

To learn more about angular acceleration, refer to:

brainly.com/question/21278452

#SPJ4

7 0
2 years ago
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