<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %
<u>Explanation:</u>
The given chemical formula of lead (IV) carbonate is 
To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

Mass of lead = (1 × 207.2) = 207.2 g
Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g
Putting values in above equation, we get:

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %
Answer:
1. Which statement correctly describes the classification of chemical reactions into different categories?
-Not all reactions fit into a category, and some reactions can fit into more than one category.
2. In a synthesis reaction, two atoms of sodium (Na) combine with one molecule of chlorine gas (Cl2) to produce sodium chloride (NaCl). How many molecules of sodium chloride are produced?
-Two
3. In the decomposition of water, why is twice as much hydrogen as oxygen formed?
- There are two atoms of hydrogen and one atom of oxygen in a water molecule.
4. Which component is transferred between substances in an oxygen-reduction reaction?
-Electrons
5. In a chemical reaction, substance A transfers electrons to substance B. Which statement is correct?
-Substance B is reduced and acts as the oxidizing agent.
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