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Alex17521 [72]
3 years ago
15

Flyer denna jetpack flyer when i leave

Engineering
1 answer:
HACTEHA [7]3 years ago
8 0

Answer:

I this a working or u just wanna text?

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6. During some actual expansion and compression processes in piston–cylinder devices, the gases have been
Katyanochek1 [597]

During some actual expansion and compression processes in piston-cylinder devices, the gases have been are the P1= P2.

<h3>What is the pressure?</h3>

Pressure is something that has the pressure that is physical and that causes the pressure is piston-cylinder devices.

During a few real enlargements and compression procedures in piston-cylinder devices, the gases were located to meet the connection PV n = C, wherein n and C are constants.

Read more about the pressure :

brainly.com/question/25736513

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5 0
2 years ago
A water reservoir contains 108 metric tons of water at an average elevation of 84 m. The maximum amount of electric energy that
zavuch27 [327]

Answer:

24.72 kwh

Explanation:

Electric energy=potential energy=mgz where m is mass, g is acceleration due to gravity and z is the elevation.

Substituting the given values while taking g as 9.81 and dividing by 3600 to convert to per hour we obtain

PE=(108*9.81*84)/3600=24.72 kWh

8 0
4 years ago
Bằng lý luận và thực tiễn, bạn hãy trình bày ý kiến của mình về quan điểm sau đây: "Quá trình dạy học là quá trình truyền thụ tr
mrs_skeptik [129]

Answer:

can you please ask in English I can't understand this language

7 0
3 years ago
Ti-6Al-4V has a fracture toughness of 74.6 MPa-m0.5. How much stress (in MPa) would it take to fail a plate loaded in tension th
Nikitich [7]

Answer:

critical stress  = 595 MPa

Explanation:

given data

fracture toughness =  74.6 MPa-\sqrt{m}

crack length = 10 mm

f = 1

solution

we know crack length = 10 mm  

and crack length = 2a as given in figure attach

so 2a = 10

a = 5 mm

and now we get here with the help of plane strain condition , critical stress is express as

critical stress  = \frac{k}{f\sqrt{\pi a}}    ......................1

put here value and we get

critical stress  = \frac{74.6}{1\sqrt{\pi 5\times 10^{-3}}}

critical stress  = 595 MPa

so here stress is change by plane strain condition because when plate become thinner than condition change by plane strain to plain stress.

plain stress condition occur in thin body where stress through thickness not vary by the thinner section.

6 0
3 years ago
Determine the maximum intensity ww of the uniform distributed load that can be applied to the beam without risk of causing the s
AnnyKZ [126]

Answer:

Please see attachment

Explanation:

Please see attachment

3 0
4 years ago
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