All categories

3 years ago

Tyquan uses the greatest common factor and the distributive property to rewrite this sum:

Mathematics

2 answers:

diamong [38]3 years ago

5 0

15 is the greatest common factor so it would be 15(5+4)

LenaWriter [7]3 years ago

5 0

Answer:3(25+20)

Step-by-step explanation: multiple the outside number (3) with the numbers inside the parentheses (25+20)

You might be interested in

X2 + 5x - 50 = 0<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%205x%20-%2050%20%3D%200" id="TexFormula1" ti

love history [14]

Answer:

x = -10

x = 5

Step-by-step explanation:

${x}^{2} + 5x - 50 = 0 \\ (x + 10)(x - 5) = 0 \\ \\ x = - 10 \\ x = 5$

8 0

2 years ago

What is the interquartile range of the data set? {18, 17, 10, 25, 20, 20, 30, 18, 18, 30, 25} Enter the answer in the box. PLEAS

sasho [114]

The interquartile is 21

7 0

2 years ago

Read 2 more answers

Matt is running in a 9 mile race over

iren2701 [21]

Answer:54 minutes

Step-by-step explanation:

9 x 5 = 45 then 45+ the.1 minute from each mile so it would be 9 +45 = 54 minutes

4 0

3 years ago

$350 in the ratio 4:3

kherson [118]

Answer:

$200 : $150

Step-by-step explanation:

Sum the parts of the ratio, 4 + 3 = 7 parts

Divide the total by 7 to find the value of one part of the ratio.

$350 ÷ 7 = $50 ← value of 1 part of the ratio

4 parts = 4 × $50 = $200

3 parts = 3 × $50 = $150

8 0

2 years ago

In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294

slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

$a_4=54$ and $a_7=1458$

To find $a_{12}:$

The given sequence is a geometric sequence.

The general term of the geometric sequence is $a_n=a_1\ r^{n-1}$ .

If we have 2 terms of a geometric sequence $a_n$ and $a_k$ (n > K),

then we can write the general term as $a_n=a_k\ r^{n-k}$ .

Here we have $a_4=54$ and $a_7=1458$ .

So, n = 7 and k = 4 ( 7 > 4)

$a_7=a_4\ .\ r^{7-4}$

$1458=54\ . \ r^3$

This can be written as

$$r^3=\frac{1458}{54}$

$$r^3=27$

$$r^3=3^3$

Taking cube root on both sides of the equation, we get

r = 3

$a_{12}=a_7\ .\ r^{12-7}$

$=1458\ .\ r^5$

$=1458\ .\ 3^5$

$a_{12}=354294$

Hence the 12th term of the geometric sequence is 354294.

7 0

2 years ago