y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
Answer:
m = 3.625
Step-by-step explanation:
1.2m + 0.65 = 5
~Subtract 0.65 to both sides
1.2m = 4.35
~Divide 1.2 to both sides
m = 3.625
Best of Luck!
Answer:
3
Step-by-step explanation:
Step-by-step explanation:
The scientific notation:
<em>1 ≤ a < 10</em> and <em>k -</em><em> any integer number</em>
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I need the picture in order to see what angle x is :)
