The answer is either A or B I’m not sure
<span>If two fluorine atoms bonded with each other what kind of bond would be involved?
A. ionic
B. valence
C. covalent
D. non-metallic
C. covalent
</span>
The balanced reaction is:
N2 + 3H2 = 2NH3
We are given the amount of the product to be produced.This will be the starting point of our calculations. We use the ideal gas equation to find for the number of moles.
<span>
n = PV / RT = 1.00(.520 L) / (0.08206 atm L/mol K ) 273 K
n= 0.0232 mol NH3
</span>0.0232 mol NH3 (1 mol N2 / 2 mol NH3) = 0.0116 mol N2
<span>Therefore, the correct answer is A.</span>
<h3>
Answer:</h3>
0.0253 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 0.456 g H₂O (water)
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of H - 1.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
![\displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.456%20%5C%20g%20%5C%20H_2O%28%5Cfrac%7B1%20%5C%20mol%20%5C%20H_2O%7D%7B18.02%20%5C%20g%20%5C%20H_2O%7D%29)
- [DA] Multiply/Divide [Cancel out units]:
![\displaystyle 0.025305 \ mol \ H_2O](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.025305%20%5C%20mol%20%5C%20H_2O)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.025305 mol H₂O ≈ 0.0253 mol H₂O