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FinnZ [79.3K]
3 years ago
15

A potter's wheel has the shape of a solid uniform disk of mass 7 kg and radius 0.65 m. It spins about an axis perpendicular to t

he disk at its center. A small 2.1 kg lump of very dense clay is dropped onto the wheel at a distance 0.41 m from the axis.
What is the moment of inertia of the system about the axis of spin?
Physics
1 answer:
ozzi3 years ago
5 0

Answer:

1.832 kgm^2

Explanation:

mass of potter's wheel, M = 7 kg

radius of wheel, R = 0.65 m

mass of clay, m = 2.1 kg

distance of clay from centre, r = 0.41 m

Moment of inertia = Moment of inertia of disc + moment f inertia of the clay

I = 1/2 MR^2 + mr^2

I = 0.5 x 7 x 0.65 x 0.65 + 2.1 x 0.41 x 0.41

I = 1.47875 + 0.353

I = 1.832 kgm^2

Thus, the moment of inertia is 1.832 kgm^2.

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A 10.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal. If there is no fricti
Alenkinab [10]

Answer:

v_f = 3.45 m/s

Explanation:

As we know that box was initially at rest

so here work done by all forces on the box = change in its kinetic energy

so we will have

mg sin\theta L = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

now we have

m = 10 kg

\theta = 10^0

L = 3.5 m

so we will have

10(9.81)sin10 \times 3.5 = \frac{1}{2}(10)(v_f^2 - 0)

2(9.81) sin10 \times 3.5 = v_f^2

so final speed is given as

v_f = 3.45 m/s

6 0
3 years ago
A race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of
noname [10]

Answer:

the acceleration of the car is 1.167 m/s²

Explanation:

Given;

initial velocity of the race car, u = 5 m/s

final velocity of the race car, v = 12 m/s

time to finish the race, t = 6 s

The acceleration of the car is calculated as;

a = (v - u) / t

a = (12 - 5) / (6)

a = 1.167 m/s²

Therefore, the acceleration of the car is 1.167 m/s²

3 0
3 years ago
Read 2 more answers
2. A Plate 0.02 mm distance from a fixed Plate moves at a velocity Of 0.6mls and requires a force of 1.962 N Per unit area to ma
Marizza181 [45]

Answer:

6.54 × 10⁻⁵ Pa-s

Explanation:

Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m

Since F = μAu/y

F/A = μu/y where F/A = force per unit area

Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²

So,  μ = F/A ÷ u/y

substituting the values of the variables into the equation, we have

μ = F/A ÷ u/y

μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m

μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s

μ = 6.54 × 10⁻⁵ Ns/m²

μ = 6.54 × 10⁻⁵ Pa-s

5 0
3 years ago
During which of the following activities may in inflatable personal flotation device to be used
Alla [95]
They may be used whenever you are not experienced with swimming and you are near the water such as swimming, canoeing, etc
5 0
4 years ago
A girl travels along the circumference of a circle of radius 14 m. What is her total distance travelled and displacement when sh
AysviL [449]

Answer:

87.976meters, 43.988 meters, 65.982 meters

Explanation:

Given data

Radius= 14m

Let us find the circumference of the circle

This is equivalent to the total distance covered

C= 2πr

C= 2*3.142*14

C= 87.976 meters

Hence the total distance is

87.976meters

The displacement when she has covered 1/2 the circle is

=87.976/2

=43.988 meters

The displacement when she has covered 3/4 the circle is

=87.976* 3/4

=65.982 meters

6 0
3 years ago
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