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FinnZ [79.3K]
3 years ago
15

A potter's wheel has the shape of a solid uniform disk of mass 7 kg and radius 0.65 m. It spins about an axis perpendicular to t

he disk at its center. A small 2.1 kg lump of very dense clay is dropped onto the wheel at a distance 0.41 m from the axis.
What is the moment of inertia of the system about the axis of spin?
Physics
1 answer:
ozzi3 years ago
5 0

Answer:

1.832 kgm^2

Explanation:

mass of potter's wheel, M = 7 kg

radius of wheel, R = 0.65 m

mass of clay, m = 2.1 kg

distance of clay from centre, r = 0.41 m

Moment of inertia = Moment of inertia of disc + moment f inertia of the clay

I = 1/2 MR^2 + mr^2

I = 0.5 x 7 x 0.65 x 0.65 + 2.1 x 0.41 x 0.41

I = 1.47875 + 0.353

I = 1.832 kgm^2

Thus, the moment of inertia is 1.832 kgm^2.

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A 500 kg car starts with a force of 1000 N
Nadya [2.5K]

Answer:

2 m/s²

30 m/s

Explanation:

1) F = ma

1000 N = (500 kg) a

a = 2 m/s²

2) Given:

v₀ = 0 m/s

a = 2 m/s²

t = 15 s

Find: v

v = at + v₀

v = (2 m/s²) (15 s) + 0 m/s

v = 30 m/s

3 0
3 years ago
SOMONE PLEASE HELP ASAP!!!!
Anna11 [10]

Answer:

from vacuum to air

Explanation:

Refraction is a property of lightwave, in which it changes speed as it passes the boundary between two media.

  • When light travels from a denser medium to a less dense medium, the light wave speeds up and bends away from the normal.
  • Also when light travels from a less dense medium to a denser medium, the light wave slows down and bends toward the normal.

The correct option must be from a less dense medium to a denser medium.

density of glass = 2500 kg/m³

density of air = 1.275 kg/m³

density of ice = 919 kg/m³

density of water = 1000 kg/m³

density of plastic = 940 kg/m³

density of vacuum = 6.5 x 10⁻²⁷ kg/m³

The two possible options are;

from ice to water

from vacuum to air

The difference in densities of ice and water is not larger compared to vacuum and air.

If you are required to choose two options, the two options are correct

But if it is only one option, then from vacuum to air is the correct answer.

Therefore, the correct option is from vacuum to air

7 0
3 years ago
Suppose 9.30 3 105 J of energy are transferred to 2.00 kg of ice at 0°C. (a) Calculate the energy required to melt all the ice i
Ratling [72]

Answer:

(a) 672000 J

(b) 258300 J

(c) 30.75 °C

Explanation:

<em>(a) Energy required to melt the ice = Latent heat of fusion of ice</em>

<em>Latent heat of fusion of ice (Q₁) = lm............................. Equation 1</em>

<em>Where l = specific latent heat of fusion of ice, m = mass of ice</em>

<em>Given: m = 2.00 kg</em>

<em>Constant : l = 336000 J/kg</em>

<em>Substituting these values into equation 1,</em>

Q₁ = 336000 × 2

Q₁ = 672000 J.

<em>Energy required to melt the ice = 672000 J</em>

<em>(b) The Energy remains to raise the temperature of the liquid water = Total Energy - Energy requires to melt  the ice.</em>

<em>Given: </em><em>Total Energy = 9.303 × 10⁵ J, = 930300 J</em>

<em>Energy remain to raise the temperature of the liquid water = </em>

<em>930300 - </em>672000

<em>Total Energy  = 258300 J</em>

Energy remain to raise the temperature of the liquid water = 258300 J.

<em>(c): Q = cmΔT ............. equation 2</em>

<em>Where c = specific heat capacity of water, m = mass of water, ΔT = change in temperature, Q = Energy required to change the temperature of liquid water  </em>

<em>Making ΔT the subject of formula in the equation above,</em>

<em>ΔT = Q/cm........................................... Equation 3</em>

<em>Given: m = 2.00 kg, Q = 258300 J</em>

<em>Constant: C = 4200 J/kg. K</em>

<em>Substituting these values into equation 3</em>

<em>ΔT = 258300/(4200×2)</em>

<em>ΔT = 258300/8400</em>

<em>ΔT = 30.75 K</em>

But ΔT = T₂ - T₁

Where T₁ initial temperature, T₂ = final Temperature

T₂ = T₁ + ΔT,

<em>Given: T₁ = 0 °C</em>

<em>Therefore,</em>

<em>T₂ = 30.75 + 0 = 30.75</em>

<em>T₂ = 30.75 °C</em>

Final temperature of water = 30.75 <em>°C</em>

6 0
3 years ago
                 Water that flows downhill along Earth's surface is called
denis23 [38]
<span>Water that flows downhill along the earth’s surface is called runoff. Runoff or also called as surface water runoff or overland flows is the flow of water when there’s excess water caused by ice melted, rain or storm. These occur because maybe the rain or the storm pours so hard and quick that the soil can’t absorb it fastly. If runoff water flows on the ground and reached a channel, it is called as nonpoint source. One example of nonpoint source are the canals full of leaves, the water can’t continue flowing because the leaves stops it.

</span>



8 0
3 years ago
An athlete is running at a constant velocity with a javelin held in his right hand. The force he is applying on the javelin as h
Paladinen [302]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Since the force he is applying is 5N and he carries it a distance of 10 meters and the displacement and the force are assumed to be in the same direction we have 5*10 <span>so 50 J </span>

5 0
3 years ago
Read 2 more answers
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